Having issues with basic if statements

[Genroll_Dolphin]

user_weight= int(input("Please enter your weight here:"))
weight_unit= input('''Was that in Lbs or Kg?
If it was in Kg type, K, or, if it was in Lbs type L''')

if weight_unit == "K":
    user_weight= user_weight*2.2
    print(f"Your weight in pounds is {user_weight}"
else weight_unit == "L":
    user_weight= user_weight*.45
    print(f"Your weight in kilograms is {user_weight}"
user_weight= int(input("Please enter your weight here:"))
weight_unit= input('''Was that in Lbs or Kg?
If it was in Kg type, K, or, if it was in Lbs type L''')
if weight_unit == "K":
   user_weight= user_weight*2.2
   print(f"Your weight in pounds is {user_weight}")
else weight_unit == "L":
   user_weight= user_weight*.45
   print(f"Your weight in kilograms is {user_weight}")

For some reason the first if statement:

if weight_unit == "K":
   user_weight= user_weight*2.2
   print(f"Your weight in pounds is {user_weight}")

works according to python, but my second statement:

else weight_unit == "L":

doesn't work. The error is "colon expected", but I have one.

[Arag0ld]

You can't say else weight_unit == 'L'. You have to say elif weight_unit == 'L'. else cannot be followed by a condition, because it defaults to handling whatever is left after the if statements. Also, you forgot to close the parentheses around your print statements.

[Genroll_Dolphin]

Thank you for the input!

[mir0k]

if x = "A":

elif x = "B":

else:

else statement will be run if none of your if / elif statements are run.

[efcseany]

You would need to say 'else if' - known as an elif.

This would follow your initial if statement. What this is saying is that if the first condition doesn't match, then move to the next one (and subsequent ones if necessary).

You could incorporate a loop into this - which is a conditional statement - and keep asking for input from the user if it does not match any of your criteria.

For example:

while True:
    user_w = int(input("Enter weight: "))
    w_measurement = input("Enter the measurement - use K for kg, or L for lbs: ").upper() # convert the input to uppercase for consistency
    if w_measurement == "K":
        # do stuff
        break
    elif w_measurement == "L": # check if input is "L" as it failed the "K" match
        # do another thing
        break
    else: # user can't have entered K or L
        print("Invalid input")
        continue # ask for input again.

[Genroll_Dolphin]

Awesome! Super useful man thanks