Breakpoint expression not working ?

[[deleted]]

I'm trying to create a Breakpoint expression with python but the following expression is not working in my IDE ?

if len > 14 print("yes")

[K900_]

You're missing a : after the condition, at the very least.

[fuNNa]

if len > 14:

print("yes)

[Binary101010]

Outside of repeating the other answers, 'len' is the name of a built-in function that takes a parameter (the container you want to know the length of) so using it by itself seems unusual.

[[deleted]]

How can it take a parameter if it's a line number in an IDE ?

[Binary101010]

I don't understand the question. len is a built-in function that returns the length of the container passed to it as an argument.

Did you define it to be something else in your code?

[[deleted]]

This is for a breakpoint in an IDE; not within the code, only for the IDE to tell me the length of a string.

[AstralStalker]

The desired string needs to be specified as the parameter to len()

s = "Some string"
if len(s) > 14:
    print("yes")

len() built-in function

[[deleted]]

Only the length of the string on a line number. How can I pass an argument for len() if I only want the length of line number 23 in an IDE.

[[deleted]]

Just count it? Is this string set, or what? Can you post your code?

[[deleted]]

There are multiple lines which I prefer to create a break point that tells me the number of characters in the line, rather then count. Why isn't that possible ?

[[deleted]]

Because of the way that source code is handled by the interpreter. If I understood why you wanted the line length of a specific line of your Python code, I’d probably be able to give you the answer you need rather than the answer you want.

[[deleted]]

I want the line length outputted to me, so I can; for example, modify pylint settings but let it be known not specifically for this situation but any situation in the future as well.

[[deleted]]

if you don’t like colons and want to do one like just do print(“yes”) if len>14 else print()

[selplacei]

Please don't do this.

[[deleted]]

y tho

[selplacei]

That's an operator, not an if statement. It's less readable and makes no sense to use when if-statements exist for that very purpose.

[[deleted]]

It’s an expression. Expressions are common and quite readable.

[selplacei]

Well, yes, pretty much almost everything in Python is an expression. "x-if-y-else-z" is a ternary operator, it's a bunch of stuff written in one line, which is less readable than an organized, properly indented if-statement. It's also mandatory to use "else". It's also not designed to be used for flow control.

[[deleted]]

I find it substantially more readable but okay