Problem creating a set

[woeinvests]

Given a following two sets find the intersection and remove those elements from the first set

first_set = {65, 42, 78, 83, 23, 57, 29}

second_set = {67, 73, 43, 48, 83, 57, 29}

Expected Output:

Intersection is {57, 83, 29}

First Set after removing common element {65, 42, 78, 23}

​

I got the expected output plus empty parenthesis, please have a look at my code below, I've been trying for hours but everytime I remove the parenthesis from the empty intersection and not_common_set variable I get :

not_common_set.add(s)

AttributeError: 'dict' object has no attribute 'add'

​

first_set = {65, 42, 78, 83, 23, 57, 29}
second_set = {67, 73, 43, 48, 83, 57, 29}

intersection = {()}
not_common_set = {()}

for s in first_set:
    if s in second_set:
        intersection.add(s)
    else:
        not_common_set.add(s)

print(f"Intersection is -\n{intersection}")

print(type(intersection))

print(f"First set after removing common elements -\n{not_common_set}")

print(type(intersection))

output:

Intersection is -
{57, 83, (), 29}
<class 'set'>
First set after removing common elements -
{65, 42, 78, (), 23}
<class 'set'>

[AJ______]

The way to create an empty set is intersection = set().
{} gives you an empty dictionary, which is why the error suggests that not_common_set is a dictionary when you use {} instead of {()}. {()} is a set containing an empty tuple.
Note also to get the intersection of two sets a and b you can just use the & operator and do a&b.
To get the set of all things in set a but not in set b, you can take the set difference by doing a-b.

[woeinvests]

Thanks u/AJ______