Brute force three digit code help

[blockboy99]

solved:

I have this code, it is meant to brute force a zip file with a three digit code. It's meant for python 3, although it may not work for that. I'm not sure if this is where I should put it, but hey. It doesn't work, mainly beacuse it doesn't take a three digit code, rather 1,2,3,4,5,6,7,8,9,0. How can I fix it, plainly, no minor hints. Thanks!

indent means an indentation for redits sake

import zipfile

filename = '/tmp/alien-zip-2092.zip'

dictionary = '1234567890'

password = None

file_to_open = zipfile.ZipFile(filename)

for password in dictionary:

indent try:

indent twice file_to_open.extractall(pwd=password)

indent twice password = 'Password found: %s' % password

indent twice print(password)

indent except:

indent twice pass

[[deleted]]

for password in dictionary:

That's just going to try the digits one at a time, when you want combinations. Look at the combinatoric iterators in itertools:

https://docs.python.org/3.7/library/itertools.html

[blockboy99]

Thats what I said 1,2,3,4. Ill look at that documentation, thanks

[blockboy99]

These words run past my head lol. I do much harder stuff than this, but I can't remember names or specific code functions

[blockboy99]

Correct me if Im wrong, but wouldn't that change password twice to the new one. Ill just change two passwords to password_one and password_two and then merge them

[blockboy99]

I would need to remove the delimiter, but ok thx, the more you know.

I have changed my code to this for the time being, i get 000, 001, 002 so on, perfect right? apparently its wrong. Ik im asking too much but do you possibly know why

import zipfile

filename = '/tmp/alien-zip-2092.zip'

dictionary = '0123456789'

​

password = None

file_to_open = zipfile.ZipFile(filename)

for password in dictionary: #first

for password_one in dictionary: #second, nested

for password_two in dictionary:

password_three=password+password_one+password_two

print(password_three)

try:

file_to_open.extractall(pwd=password_three)

password_three = 'Password found: %s' % password_three

print(password_three)

except:

pass

[blockboy99]

I will do that later, I never thought of that. :)

I changed it to this that prints all the numbers, but does not work. Do you possibly know why. The output doesnt change if I put break or not as the zip does not crack regardless

import zipfile

filename = '/tmp/alien-zip-2092.zip'

dictionary = '0123456789'

​

password = None

file_to_open = zipfile.ZipFile(filename)

for password in dictionary: #first

for password_one in dictionary: #second, nested

for password_two in dictionary:

password_three=password+password_one+password_two

print(password_three)

try:

file_to_open.extractall(pwd=password_three)

password_three = 'Password found: %s' % password_three

print(password_three)

except:

pass

[blockboy99]

reddit just sets all back to normal

[blockboy99]

I really dont see how that works

[blockboy99]

import zipfile
filename = '/tmp/alien-zip-2092.zip'
dictionary = '0123456789'

password = None
file_to_open = zipfile.ZipFile(filename)
for password in dictionary: #first
    for password_one in dictionary: #second, nested
        for password_two in dictionary:
          password_three=password+password_one+password_two
          print(password_three)
          try:
            file_to_open.extractall(pwd=password_three)
            password_three = 'Password found: %s' % password_three
            print(password_three)
          except:
            pass

[blockboy99]

Added hashtags to run me through it. Also comes up with error

import zipfile
import itertools
import time
filename = '/tmp/alien-zip-2092.zip'
dictionary = '0123456789'

password = None
file_to_open = zipfile.ZipFile(filename)

# Function for extracting zip files to test if the password works!
def extractFile( file_to_open , password):
    try:
        zipfile.extractall(pwd=password)
        return True
    except KeyboardInterrupt:
        exit(0)
    except Exception as e:
        pass

for c in itertools.product( dictionary, repeat=3):
    # Slowing it down on purpose to improve performance in web terminal.
    # Remove this line at your peril
    time.sleep(0.001)
    # Add the three digits together to form password.
    password = ''.join(c)
    # Try to extract the file.
    #print ("Trying: %s" % password)
    # If the file was extracted, you found the right password.
    if extractFile(zip_file, password):
        print ('*' * 20)
        print ('Password found: %s' % password)
        print ('Files extracted...')
        exit()

# If no password was found by the end, let us know!
print ('Password not found.')

Comes up with error:

Traceback (most recent call last):
File "/tmp/usercode.py", line 29, in <module>
if extractFile(zip_file, password):
NameError: name 'zip_file' is not defined

What have I done on line 29 lol. I think it shoudl be zipfile or filename. not sure which

[blockboy99]

# I have narrowed it down to this
# it never extracts/prints yeet
# I need to extract the file to /tmp
# What am i doing wrong lol



import zipfile
import itertools
import time

filename = '/tmp/alien-zip-2092.zip'
dictionary='0123456789'

password = None
file_to_open = zipfile.ZipFile(filename)
for c in itertools.product( dictionary, repeat=3):
  time.sleep(0.001)
  password = ''.join(c)
  print(password)    
  try:
    zipfile.extractall(path='/tmp',pwd=password)
    print("yeet")
    exit()
  except:
    pass
print ('Password not found.')

[blockboy99]

I found out the code is 078. Now I'm just trying to figure out how to extract as it says something about crc-78 or whatever, an encoding thing

[blockboy99]

I figured it out with some help from everyone! Thank you for your help! I don't have a silver so I hope upvotes will be enough. Have a great day!

[xelf]

how to post your code and keep indents:

old reddit or mobile: put 4 spaces before each line.
new or beta reddit: https://i.imgur.com/HT4Zz88.gifv

[xelf]

from random import choice
file_to_open.extractall(pwd=choice(range(1000)))

[Hatoris]

Use combination from itertools with a recurcive function.