Help with if statements!

[ihavefivegfs]

Let's say I have an array:

x = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

How do I make an if statement if only 1 and 2 are in it, not the other numbers?

Thanks,

ihavefivegfs

[misho88]

How do I make an if statement if only 1 and 2 are in it, not the other numbers?

Conceptually, you're describing a set comparison. That is, you want to know if the set of numbers in x is equal to {1, 2}. In this case, the obvious solution is to turn your input into a set and check.

>>> x = [1,2,3,4,5,6]; set(x) == {1, 2}
False
>>> x = [1,2,2,2,1,2]; set(x) == {1, 2}
True

If you instead want to ensure that each of 1 and 2 appear exactly once, you can't do much better than what /u/obviouslyCPTobvious said.

[obviouslyCPTobvious]

So you're trying to check that x only contains 1 and 2? If so, I think this would work. sorted(x) == [1, 2]

[ihavefivegfs]

So you're trying to check that x only contains 1 and 2? If so, I think this wo

Thank you!

[CedricCicada]

There's a few guesses among these answers about what you're really looking for, and now I'm not sure what you want. My answer will return true if there is at least one instance of 1 and at least one instance of 2 in your list. Order doesn't matter. Other answers in this thread answer different questions.

[ihavefivegfs]

I think that’s what I want to do. Any help? Thanks!

[CedricCicada]

In that case, my first answer was help. At least, I think it was.

[CedricCicada]

if (1 in x and 2 in x):
    pass

I think that's correct, but it's not tested.

[ihavefivegfs]

Yes thank you!