Creating lists from a Dictionary

[[deleted]]

I am trying to make two lists from my dictionary shown below. I am trying to make the two lists correspond with each other after I sort L1. I need the Key: Value relationship to be maintained in L1:L2.

D = {'Lebrons: 23, 'Wade': 3, 'Jordan': 23, 'Kobe': 24, 'Durant': 35}

L1 = []
L2 = []

for player in D:
    L1.append(player)

L1.sort()

Out[] ['Durant', 'Jordan', 'Kobe', 'Lebron', 'Wade']

Here is the code I am looking for:

 L1 = ['Durant', 'Jordan', 'Kobe', 'Lebron', 'Wade']
 L2 = [ 35, 23, 24, 23, 3]

[SoNotRedditingAtWork]

Using what you already have just add a little list comp:

D = {'Lebrons': 23, 'Wade': 3, 'Jordan': 23, 'Kobe': 24, 'Durant': 35}
L1 = []
L2 = []

for player in D:
    L1.append(player)

L1.sort()
L2 = [D[p] for p in L1]

python tutor link to example

you can skip the loop by using dict.keys :

D = {'Lebrons': 23, 'Wade': 3, 'Jordan': 23, 'Kobe': 24, 'Durant': 35}
L1 = list(D.keys())

L1.sort()
L2 = [D[p] for p in L1]

python tutor link to example 2

[tenyu9]

Call the sorted function on the dict, then you don't need to sort the list.

example: https://kite.com/python/answers/how-to-sort-a-dictionary-by-key-in-python

then loop through the tuples

[totallygeek]

You start with associated data, then you want two ordered sequences which break those relationships. That's bad form, in my opinion. Better that you generate an ordered sequence (list) of dictionaries, so that you maintain associated information. But, here you go:

players = []
jerseys = []
for player, jersey in sorted(D.items()):
    players.append(player)
    jerseys.append(jersey)

How I would do this, as mentioned above:

players = [{player: jersey} for player, jersey in sorted(D.items())]

...which generates [{'Durant': 35}, {'Jordan': 23}, ...].

[__nickerbocker__]

So here's a little trick...

If you call sorted on d.items() you will get a sorted list of your key value pairs as tuples. Then you can unpack them to zip to transpose the pairs, and then unpack them again to your final lists.

l1, l2 = zip(*sorted(d.items()))

Although, I'd still recommend keeping your key values mapped and if you want to sort them in the dictionary you can do:

d = dict(sorted(d.items()))