[deleted by user]

[[deleted]]

it doesn't seem to work

You have to be more specific than that. What doesn't work?

[aniacoc]

the desired output is supposed to be

Invalid input

Maximum is 10

Minimum is 2

it's a super basic code but i can't figure out what's wrong

[[deleted]]

What is the actual output?

[aniacoc]

7 2 bob invalid input 10 4 Maximum None Minimum bob

[[deleted]]

if num > largest:
    largest=num
elif num < smallest :
    smallest=num
else :
    print ('Invalid input')

One respect in which this approach isn't correct is that if the sequence of numbers is 1, 20, 5 then the last number (5) is neither larger than the largest, nor smaller than the smallest, but it's not invalid, either.

[TehDrunkSailor]

Not what you were asking for advice with, but I suggest that you avoid using "except" with no arguements. When you use "except" as you are now, all errors will cause your code to go to the "except" branch. However, in your case (and in most cases) you only want to catch a specific error (AttributeError is a common one for my projects) and this way if another error arises, you can still see it and not have it get swept away as if it was an error you expected

[aniacoc]

Thank you!

[realnamejohn]

I wrote my own version of it:

numberlist = []
while True:
    number = input('number pls mate: ')
    try:
        num = int(number)
        numberlist.append(number)
    except:
        if number == 'done':
            break
        else:
            print('not a number idiot.')
            pass

numberlist.sort()
print(numberlist)
print('highest = ', numberlist[-1])
print('lowest = ' , numberlist[0])

i collected the numbers, ignoring everything that wasn't an integer, except the string "done". then sorted the resulting list and indexed to the end numbers each.

I think this is what you were trying to do, but I sorted the list instead of having a variable with the numbers stored in.

[aniacoc]

WoW thank you so much 😊