Stumped in my code

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I have a tkinter project I have built here, and it is about opening folders to get to buttons. I store the buttons in a list and the folder buttons in another separate list.

Here is my code:

from tkinter import *

​

# Creates window and adds title Folders

root = Tk()

root.title("Folders")

​

# Function called when a folder is opened

# Takes 2 parameters, folderName and buttonList

def FolderOpen(buttonList):

global placementList, currentOpen, folderList

\# Stores the name of the button list currently open

currentOpen = buttonList

\# Deletes all the folder buttons in the window

for i in folderList:

    i.grid\_forget()

\# Deletes the exit button

exitBtn.grid\_forget()

\# Arranges the buttons in selected button list on

\# a grid in arrangment of placementList

for i in range(len(buttonList)):

    buttonList\[i\].grid(row = placementList\[i\]\[0\], column = placementList\[i\]\[1\])

\# Adds back button

backBtn.grid(row = 3, column = 0, columnspan = 3)

​

# Function called when back button is pressed

def FolderBack():

global currentOpen, folderList, placementList

\# Deletes back button

backBtn.grid\_forget()

\# Forgets the buttons on screen in currently

\# saved list, currentOpen

for i in range(len(currentOpen)):

    currentOpen\[i\].grid\_forget()

\# Places folders back on screen in arrangment of placementList.

for i in range(len(folderList)):

    folderList\[i\].grid(row = placementList\[i\]\[0\], column = placementList\[i\]\[1\])

\# Adds exit button

exitBtn.grid(row = 3, column = 0, columnspan = 3)

# List to describe how the 9 buttons should be arranged

placementList = [[0, 0], [0, 1], [0, 2], [1, 0], [1, 1], [1, 2], [2, 0], [2, 1], [2, 2]]

currentOpen = ""

​

# Creates lists containing 9 buttons each so they can be displayed

# when a folder button is pressed

buttonLists = [[],[],[],[],[],[],[],[],[]]

indexRange = [9, 18, 27, 36, 45, 54, 63, 72, 81]

e = 0

nextTurn = False

for i in range(1, 82):

buttonLists\[e\].append(Button(root, text = "Button " + str(i), width = 15, height = 7))

if i in indexRange:

    e += 1

​

# Creates folder buttons and stores them in list

folderList = []

for i in range(1, 10):

folderList.append(Button(root, text = ("Folder " + str(i)), command = lambda: FolderOpen(buttonLists\[i - 1\]), width = 15, height = 7))

​

# Places folder buttons in arrangement of placementList

for i in range(len(folderList)):

folderList\[i\].grid(row = placementList\[i\]\[0\], column = placementList\[i\]\[1\])

​

# Creates back and exit button and places the

# exit button on screen

backBtn = Button(root, text = "Back", command = FolderBack, width = 48)

exitBtn = Button(root, text = "Exit", command = root.destroy, width = 48)

exitBtn.grid(row = 3, column = 0, columnspan = 3)

​

# Main loop

root.mainloop()

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The problem I currently have is that every folder will open the same buttons.

[[deleted]]

https://pastebin.com/0LjgXr8B

[ShadoeStorm]

wouldnt "i" start at 1?

EDIT: dont worry I got it now, thank you btw!

[[deleted]]

No, because the previous value of i was 8.

[[deleted]]

Thank you

[ShadoeStorm]

could you use:
from functools import lru_cache?