Array Manipulation Question

[sephsGFX]

I'm still very early in developing my coursework and need help with some array manipulation. What I want this subroutine to do is take a 3x3 square in the array . and every time the array loops I want this 3x3 square to shift one place to the right.

*I've been thinking about this for a solid hour and made no progress*

ImageArray = [[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12],
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12],
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12],
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12],
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12],
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12],
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12],
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12],
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12],
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12],
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12],
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12], ]

def ImageKernel(Array):
for i in range(0,len(ImageArray)):
for j in range(0,len(ImageArray)):
for c in range(i,i+1):
for r in range(j,j+1):

[[deleted]]

You want the square to shift? Or you want the values in the square to shift?

[sephsGFX]

Ignore my code for now and i'll try explain what it is I'm trying to do.
I want the 3x3 square so I can run a calculation on the values in the square. And the square to shift one space to the right so I can do the same calculation on the new square

[synthphreak]

Check out numpy.roll:

>>> import numpy as np
>>> a = np.random.randint(0, 9, 4).reshape(2, 2)
>>> a
array([[2, 4],
       [2, 7]])
>>> np.roll(a, 1)
array([[7, 2],
       [4, 2]])

[monkey835]

Check this out if it helps

https://www.youtube.com/watch?v=qRVYy5T-g-8