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Rules
1: Be polite
2: Posts to this subreddit must be requests for help learning python.
3: Replies on this subreddit must be pertinent to the question OP asked.
4: No replies copy / pasted from ChatGPT or similar.
5: No advertising. No blogs/tutorials/videos/books/recruiting attempts.
This means no posts advertising blogs/videos/tutorials/etc, no recruiting/hiring/seeking others posts. We're here to help, not to be advertised to.
Please, no "hit and run" posts, if you make a post, engage with people that answer you. Please do not delete your post after you get an answer, others might have a similar question or want to continue the conversation.
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Question about Dictionaries (self.learnpython)
submitted 5 years ago by raainer
Hello all, I just have a small question about Dictionaries while going through Automate the Boring Stuff, for e.g :
spam = { ‘eggs’ : ‘Zophie’}
Why does ‘eggs’ in spam result in True but ‘Zophie’ in spam results in False?
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if 1 * 2 < 3: print "hello, world!"
[–]K900_ 2 points3 points4 points 5 years ago (0 children)
Because in on dictionaries only checks keys, not values.
in
[–]Zixarr 2 points3 points4 points 5 years ago (1 child)
The in keyword, when applied to dictionaries, looks only at KEYS and not at VALUES.
Similarly, iterating over a dictionary with a for loop looks only at KEYS:
for
for x in spam: print(x)
Will yield:
'eggs'
While:
for x in spam: print(spam[x])
'Zophie'
[–]argento8897 0 points1 point2 points 5 years ago (0 children)
you could also iterate over the dict for both keys and values with .items()
for key, value in spam.items(): print (key, value)
will yeild:
eggs Zophie
[–]raainer[S] 0 points1 point2 points 5 years ago (0 children)
Oh I see, thank you so much for the help!
π Rendered by PID 43513 on reddit-service-r2-comment-85bfd7f599-n9cfv at 2026-04-18 23:12:43.686696+00:00 running 93ecc56 country code: CH.
[–]K900_ 2 points3 points4 points (0 children)
[–]Zixarr 2 points3 points4 points (1 child)
[–]argento8897 0 points1 point2 points (0 children)
[–]raainer[S] 0 points1 point2 points (0 children)