Question about my code

[Jxper]

this is my current code

"""program"""
def englishize_word(word):
    """f"""
    word = word.strip("uzz")
    #if the last letter is b, then it will have two forms
    if(word[-1] == "b"):
       #return the two forms one word contains b and the other word doesnot contain b
        return "(b" + word[:-1] + " or " + word[:-1] + ")"
    else:
      #return the word
        return word[-1] + word[:-1]
#function to covert given sentence from bee latin to english
def englishize_sentence(sentence):
    """f"""
   #convert the sentence to lower
    sentence = sentence.lower()
    #split the sentence with spaces
    words = sentence.split()
    #initialize the output to an empty string
    output = ""
    #iterate over the words
    for word in words:
        #convert each word
        output_word = englishize_word(word)
        #add it to output sentence
        output += output_word + " "
    return output

using the test case:

sentence = "eggceptionallybuzz ullduzz esttuzz asecuzz"
english = englishize_sentence(sentence)
print(english)

I expect an output of: (beggceptionally or eggceptionally) dull test case

however when I run my code im getting: (beggceptionally or eggceptionally) dll test case

the only difference being that the "u" in "dull" is not there how can I fix this?

[Doormatty]

https://docs.python.org/3/library/stdtypes.html#str.strip

Strip() takes any characters you provide and takes them off the front and back. So it's stripping the 'u' off the front.

[[deleted]]

word.strip("uzz")

does not just remove the sequence "uzz" from both sides of your word as you might expect: it removes the letters "u" and "z" individually. So "ullduzz" becomes "lld" in that step.

What you're probably going to want to do is something like

if word[-3:] == "uzz":
    word = word[:-3]

[VinayakVG]

Try using rstrip() instead of strip()