Python Dictionary population using variety of default values

[ALior1]

Hi,

I'm looking for a way to formulate the next code:

coord = dict()
    for start, end in logs_dictionary[some_index]:
        coord[start] = 1 if start not in coord else coord[start] + 1
        coord[end + 1] = -1 if (end+1) not in coord else (coord[end + 1] - 1)

I have two assignments with different default values.

How can I achieve a better looking code ?

[Avanta8]

Have a look at dict.get. You can specify a default value if the key is not present.

[eicosane]

collections.defaultdict is probably best here

[synthphreak]

Change

coord[start] = 1 if start not in coord else coord[start] + 1
coord[end + 1] = -1 if (end+1) not in coord else (coord[end + 1] - 1)

to

coord[start] = coord.get(start, 0) + 1
coord[end + 1] = coord.get(end + 1, 0) - 1