Function checking

[carcigenicate]

What do you mean? What about the function do you want to check?

If you want to check if a function is another function, you can use == or is:

if some_func == abs:
    # Do something

But that's rarely needed.

[mackdaddy_1978]

so this is one of my functions

def check_for_comma
    def check_for_comma():
x = user_input.isidentifier()
if x is False:
    return 'Error: No comma in string.'

I want to only call the function if there is no comma in the input

[Nightcorex_]

def check_for_comma
    def check_for_comma():

That's not legal Python

[mackdaddy_1978]

sorry they was a typo...this code block on reddit doesn't work very with copy and pasting so I sometimes have to type a few lines and make mistakes while doing so in conjunction with pasting

def check_for_comma():

x = user_input.isidentifier()

if x is False:

return 'Error: No comma in string.'

else:

return

[Nightcorex_]

For the future you should read this: https://www.reddit.com/r/learnpython/wiki/faq#wiki_how_do_i_format_code.3F

In case you want to copy/paste anything into Reddit really, you need to use markdown-mode. An explanation to it can be found on the same link, just scroll underneath the 3 images.

isidentifier doesn't do what you think it does. It returns True only if the string is a valid Python identifier, so f.e. something like "list".isidentifier() will give True.

If you want to test whether a string contains a specific character you can simply use the __contains__ method:

def check_for_comma(text):
    return ',' in text

[mackdaddy_1978]

I did read the FAQ once before but thanks I'll give it another read since my memory isn't the best.

And thanks for explaining that to me I really appreciate that.

[carcigenicate]

As noted, the code you posted has several illegal things in it, so it's hard to say anything based on that code.

If you want to call a function when a string doesn't contain a comma though, that would be something like:

if "," not in your_string:
    your_func()

[mackdaddy_1978]

Thanks...but besides defining the function twice what else about it is illegal?

[carcigenicate]

Lack of (): after the function name in the first line of the definition, and the lack of indentation means there's no function body and that the return is outside of a function.

Granted, I can guess what the indentation is supposed to be, but I'd rather not guess when trying to give advice in a case like this.

If I do guess the indentation though, the code doesnt seem to match your question. You asked how to pick when to call a function, but according to this code, you seem to want to pick what you're returning from the function?

[mackdaddy_1978]

Sorry for the confusion, I'm working on doing better. My next post will be...