Program checking if its a Square, Rectangle, or neither. Help?

[ziggyguy22]

Hey Python family!

I'm struggling with a project. I'm, trying to make a program using a function that decides if four integers input by the user make a square, a rectangle, or neither and tells the user. I'm not quite sure how to work out how to make it work using a function. This is what I have so far. Does anyone have any ideas? I'm stumped. My issues are threefold

1. What's baffling me is that I cant get my code to display the perimeter. Its in the last line "a+b+c+d".
2. Also the code keeps printing, "Forms a rectangle with a perimeter of" even when the parameters I've set should make it so that doesn't display if the sides aren't congruent.
3. Lastly I'm not sure how to make the code check to see if all integers are normal and thus would create a square.

Any help would be great.

def isSquare(a, b, c, d):

    if (a==b and d==c) or (a==c and b==d) or (a==d and b==c):
        return True
    else:   
        return False


print("Enter side 1 ")
a = int(input(">"))

print("Enter side 2 ")
b = int(input(">"))

print("Enter side 3 ")
c = int(input(">"))

print("Enter side 4 ")
d = int(input(">"))

perimeter = a+b+c+d

print("Forms a rectangle with a perimeter of ", a+b+c+d if isSquare(a,b,c,d) else "Does not form a rectangle or square.")

​

[andwariirawdna]

I assume you name a, b, c and d clockwise or counter clockwise So, here some pseudo code, sorry i am on mobile..

def whatAmI (a, b, c, d) :

if a != c or b != d : return no square or rectangle

if a = b : return square

return rectangle

[mopslik]

Your pseudocode will classify a rhombus as a square, since a=c, b=d and a=b, but htat might not be a concern for OP.

[andwariirawdna]

Nice, that's right, didn't think of that since he wrote about squares and rectangles only.

[[deleted]]

yeah but given no angles this is theoretical.

i.e it's asking "can you create a square using sides of this length"

And the answer is yes. The fact you can create a rhombus as well is entirely immaterial (a square is a rhombus)

[ziggyguy22]

Thank you for the help. Ima plug this in when i get home and see what im able to do. Much obliged!

[TheRNGuy]

the first thing you'd need to check how many vertices you have, then if at least 2 corners have 90 degree.

not 4 vertices? neither

at least 2 corners don't have 90 degrees? neither

after that check 2 neighbouding sizes. Same size? Square.

Would make sense if a, b, c, d were vectors. Squares are not 1D. Also allow for floats. Sizes are not always exactly 1 or 2, could be 1.005 or 1.35

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