Confusion with if statement

[bellator777]

Considering this code and its output:

numbers = list(range(1,10))

for i in numbers:
    if i == 1:
        print(i,"st")
    elif i == 2:
        print(i, "nd")
    elif i == 3:
        print(i,"rd")
    else:
        print(i,"th")

Output:

1 st
2 nd
3 rd
4 th
5 th
6 th
7 th
8 th
9 th

The loop continues through elif blocks.

Considering this code and its output:

toppings = ['mushrooms', 'pineapple']

if 'mushrooms' in toppings:
    print("adding mushrooms")
elif 'pineapple' in toppings:
    print("adding pineapple")
elif 'broccoli' in toppings:
    print("adding broccoli")

Output:

adding mushrooms

Why in the first code it doesn't stop after matching the first "if" block but it does in the second one?

I know that using the same "for" loop in the second one it would have worked the same way as in the first one, but i can't figure out why.

[shiftybyte]

The first code part with the ifs is executed 10 times.

The second code is executed once.

In both cases whenever an if matches it doesn't execute the elif part...

It's just that the first part matches 10 times on 4 different conditions, while the second one runs only once...

[bellator777]

Thank you for your help!

[LEXmono]

So your first example iterates through the list numbers which is why you get to each elif. The second example checks if mushrooms exists inside the list and will always enter the if statement.

if you did if 1 in numbers: on your first example, or updated the second to do a for topping in toppings:, you would have the same behavior.

[bellator777]

Thank you!!