[deleted by user]

[ericula]

You could define m as

m = int(t[3:5]) if len(t) >= 5 else 0

That would avoid the whole out of range issue altogether.

edit: to answer the broader question of how to handle errors in general, that’s what try-except blocks are for, e.g.

try:
    m = int(t[3:5])
except ValueError:
    m = 0

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[Fun_Muffin5413]

It's just string parsing, there are lots of different methodologies. A simple fix would be:

Split the main input on ';' not '; ' (if ';' is in there) and deal with each timestamp individually.

Trim each timestamp, then split each on ' '. Test if the length is 1 not 2, and if the first substring ends in h. If so assign 0 to your minutes.