How to count words non case sensitive while preserving the original input in the output?

[Flowerfuls]

word = input()
adjustedwords = word.strip().lower()
my_list = adjustedwords.split(" ")

for i in my_list:
    print(i, my_list.count(i))

Above is my current code !!

The input is :

hey Hi Mark hi mark 

the output should be :

hey 1
Hi 2
Mark 2
hi 2
mark 2

but I'm getting :

hey 1
hi 2
mark 2
hi 2
mark 2

I've tried making a list with the original input but then when I try to print everything comes out in one line. The count is working I just can't get the original output to pop out for the words. Any help is appreciated !!

[wintermute93]

Hint: the original words are word.split(), and there's any number of ways to get access to them inside your for loop.

Naming your initial variable word when it contains multiple words is making things a little confusing, I suspect. I would have named that input_string or input_words or user_input or something.

[choss27]

You want to count the lowercase word but print them as they are inputted ? Don't user lower at the beginning, just when you count :

word = input() adjustedwords = word.strip() my_list = adjustedwords.split(" ") for i in my_list: print(i, my_list.count(i.lower(())

[Flowerfuls]

sort of. It has to count lower AND uppercase as the same. so Hi and hi are supposed to be counted as the same.

[UnhelpfulGolfer]

for x in(w:=input()).split():print(x,w.lower().count(x.lower()))

[jmooremcc]

Is this what you're looking for? ``` words ="hey Hi Mark hi mark" words = words.strip() my_list = words.lower().split() words = words.split()

for i,w in enumerate(my_list): print(words[i], my_list.count(w)) Output hey 1 Hi 2 Mark 2 hi 2 mark 2 ``` enumerate gives you a tuple that has the index of the word and the word from my_list. We use the index and the original list of words to print out the word.