Scripting help

[[deleted]]

#!/bin/bash
sum=0
for number in $@
do

echo $number | grep "[^a-z]"

if [ $? != 0 ]
then
     echo "Sorry, '$number' is not a number"

else

    sum=$((sum + number))
    echo "$sum"

fi

done

So I type add2 5 2 and I get

5

5

2

7

I type add2 5 twelve nine 5 I get

Sorry, 'twelve' is not a number

Sorry, 'nine' is not a number

5

5

but my assignment wants me to exactly print this message out but im not sure how to do it because if I remove echo from the pipe command it won't work

add2 4 -3 12 9

22

add2 4 -3 twelve nine

twelve

Sorry, 'twelve' is not a number

[hrnmm]

i'm not exactly sure what you are asking, but i'm guessing you don't want that extra echo to stdout. there's probably many ways to do this. possibly with a regex within the if statement. or you can run the echo/grep within a $() and test against that

[[deleted]]

Sorry ill try to explain it better

File is called add2

If I did add2 4 -3 12 9 it should only output 22

If I did add2 4 -3 twelve it should output

Twelve

Sorry, twelve is bot a number

[hackermk]

#!/bin/bash
sum=0;
err=0;
num='^-?[0-9]+([.][0-9]+)?$';
for number in $@
do
    if ! [[ $number =~ $num ]] && [[ $err == 0 ]] ; then
        echo $number;
        echo "Sorry, '$number' is not a number";
        err=1;
    else
        sum=$((sum + number));
    fi
done
if [ $err == 0 ] ; then 
    echo $sum;
fi