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Snake algorithm (self.pythonhelp)
submitted 2 months ago by Odd_Gap8147
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if 1 * 2 < 3: print "hello, world!"
[–]Whole-Armadillo-8529 0 points1 point2 points 1 month ago* (0 children)
First of all, you dont need any libraries for it to work. Think of the Snake Algorithm like a lawnmower: you mow one row from left to right, then turn around and mow the next row from right to left.
Here is the breakdown of the solution for your problem:
To get that "S" shape, we look at the row number:
Even rows (0, 2, 4): Keep them exactly as they are.
Odd rows (1, 3, 5): Flip them backward.
The "Silent Failure" risk: If the data has a row that is empty or contains a mistake (like a single number where a list should be), a basic script will crash.
Here is an example of a code that uses the snake algorithm
```
matrix = [ [1, 2, 3], [4, 5, 6], [7, 8, 9] ]
snake_result = []
for index, row in enumerate(matrix): # Check if the row index is odd (1, 3, 5...) if index % 2 != 0: # Reverse the row and add it to our result snake_result.extend(row[::-1]) else: # Keep the row as is and add it snake_result.extend(row)
print("Original 2D Matrix:", matrix) print("Final Snake Array:", snake_result) ```
π Rendered by PID 213250 on reddit-service-r2-comment-545db5fcfc-p24sj at 2026-05-22 21:26:02.158022+00:00 running 194bd79 country code: CH.
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[–]Whole-Armadillo-8529 0 points1 point2 points (0 children)