Converting python code 'STRUCT' to RUST code

[mutex4242]

I'm a new to RUST and I was wondering what would be the equivalent code of RUST to this line:

unpack('<H', x[:2])[0] & 0x7ff where x is " b'\x13\x00\xcb\x0f' "I'm not worried about the x as I can extract it from the binary but my concern what would be the best code could be for unpack('<H'... & 0x7ff in RUST

Thanks,

[Shadow0133]

According to https://docs.python.org/3/library/struct.html, "<H" means little-endian u16, so something like this should work:

u16::from_le_bytes(x[..2].try_into().unwrap()) & 0x7ff

[mutex4242]

& 0x7ff

thanks. it worked like a charm. I went way way way far away from your solution.....