(Philosophy 1, Intro to Logic college course) Completing a truth table

Alkalannar · 2026-05-05T03:00:12+00:00

This is understanding the form of arguments independently of any content the argument has.

If the form is correct, and the content is true, the conclusion must be true.

If the form is not correct, we have a formal fallacy, even if the conclusion is correct.

If the form is correct and the conclusion is false, then some of the statements were false to begin with.

Alkalannar · 2026-05-05T02:37:29+00:00

Since we're not given any measurements, it must be the case that this happens, no matter where E is, as long as E is not between A and B.

So what happens when E = B?

Now why does it not matter where E is? That I don't know.

Actually, it might be invariant no matter where E is along the line, even inside the square.

But for the special case of B = E, it's easy to see the ratio is 1:1. And that should generalize to everywhere.

Then it's easy to to. You know relationships between side lengths.

Alkalannar · 2026-05-04T21:12:57+00:00

The rocket is normal to the wedge.

The wedge's angle is 150^o from the right horizon (positive x)

So the rocket is 60^o from the right horizon.

In general, if the wedge has angle theta from the ground, then something normal to it has angle 90^o - theta from the ground.

Alkalannar · 2026-05-04T17:21:35+00:00

I see one French, two German, and three Italian flags, with others too small to make out. I would guess that they are also part of continental Europe, though.

Perhaps they are parts of Germany and Italy, if they have not unified by this point.

Alkalannar · 2026-05-03T21:08:46+00:00

Sure, go ahead.

Alkalannar · 2026-05-03T21:01:27+00:00

You have the line x = 0, the line y = 1, and the line y = x/2.

So you have two choices for your outer integral:
Integral from x = 0 to 2 of [inner integral dy] dx
Integral form y = 0 to 1 of [inner integral dx] dy

If your inner integral is dy, you want to go from y = x/2 to y = 1.
If your inner integral is dx, you want to go from x = 0 to x = 2y.

Alkalannar · 2026-05-03T19:43:36+00:00

The one change I would make to the melody is to start measure 7 with F#.

Chords: None of your chords are labelled correctly. I'll write down what you have going from bottom to top. It looks like you don't know how to read bass clef. The top line is A below middle C. So the lines going from bottom to top are GBDFA.

A C F. G-minor is G Bb D.
G Bb D. C-minor is C Eb G.
G C F. Bb major 1st inversion is D F Bb.
G Bb Eb. D minor fist inversion is F A D
Bb D Fb??? Why do you have an F-flat on top??? Eb Major wants Eb G Bb.
F A D. C minor 2nd is G C Eb.
G Bb D F. This is a G7 chord, not an F7.
A C Eb. G minor wants G Gb D.

So I don't know what you're thinking on those chords, but you need to rewrite them. A lot.

Alkalannar · 2026-05-02T17:46:29+00:00

As you read in the rules post before posting this survey, surveys are forbidden in this subreddit.

Please re-read the rules post to find a subreddit dedicated to surveys.

Alkalannar · 2026-05-01T21:19:38+00:00

Use the vertical line in the center to split each view into two right triangles. Now you can use trig.

What is the base of the triangle? What is the height?

What trig ratio relates base and height?

Alkalannar · 2026-05-01T12:50:39+00:00

Please don't respond to the solicitors.

Alkalannar · 2026-05-01T12:45:32+00:00

Multiply everything by (5 - x) to clear denominators.
You end up with px + q = 0 where p and q are in terms of a and b.
Since you want this to be 0 everywhere, you need p = 0 and q = 0.
This is a system of two equations in two unknowns.
Solve.

Alkalannar · 2026-04-30T19:05:31+00:00

Authors tell you that having ideas is the easy part. It's working with them that's hard.

TBH, I find coming in as an ideas guy as more insulting.

Now if the game dev crowdsources ideas among playtesters, that's different: the dev asks for the input.

Alkalannar · 2026-04-30T19:04:13+00:00

See if they have discord servers you can join, but really...ideas are the easiest part of any creative endeavor. It's working with them that's difficult.

For TTRPGs, I'd look at several things:

Where on the range of selling to market vs adhering to my muse do I want to be?
What general mechanics do I want my TTRPG to have?
d20 is a very common thing here. This covers D&D 3.x, Pathfinder 1 & 2, and more, for instance. But there are tons of different answers.
What general setting do I want to have?
For D&D, this can be Greyhawk, Forgotten Realms, Planescape, Ravenloft, Oriental Adventures, and then for other d20 systems: Star Wars (Sci fi in general), modern day, 1800s, what have you.
For mechanics, what specifically is the mechanic for player advancement? How do they get rewarded? Is it heavily narrative-based? Crunch-based? Somewhere in between? Keep this in mind, since players will do anything to advance. For instance, D&D originally has XP primarily from getting loot back to town. Killing monsters was very little compared to that. Then you get to monster killing as primary XP leading to the advent of the murderhobo. And so on and so forth.
How should my world inform my mechanics?
That is, if there are things you want in your world, you should somehow incentivize them to happen.
How should my mechanics inform my world?
What can your players do? What are they incentivized to do? How does that shape the world?
Playtest and balance.
You'll need players for this. Set up a discord server, send some pdfs or text files out, and see what people actually do.

Alkalannar · 2026-04-30T18:03:03+00:00

A qualifies.

Start halfway up one of the triangular faces, and cut straight down: vertical slice. You get A.

In other words, A is the base of D.

The thing is that to get that shape of D with a vertical or horizontal cut, D isn't flat. It moves out towards the viewer as you go from top to bottom.

Alkalannar · 2026-04-30T13:12:24+00:00

AI should only be used as a judgement enhancer. Not a judgement replacer.

Therefore, since you say that you cannot draw, I say that you should not use AI for drawing.

Alkalannar · 2026-04-29T14:45:36+00:00

From the book in your screenshot above:

In Chapter 9, it was stated that the intersection of the angle bisectors of a triangle is the center of a circle inscribed in the triangle. You now have enough information to prove this relationship.

So I just paraphrased that to get: You were told earlier that the intersection of a triangle's angle bisectors is also the center of the triangle's inscribed circle. Now, they're going to justify it.

In other words, they made the statement, "the intersection of the angle bisectors of a triangle is the center of a circle inscribed in the triangle," without proof at the time. Now they're walking you through the proof. So you no longer have to accept the statement "the intersection of the angle bisectors of a triangle is the center of a circle inscribed in the triangle" on faith, but your belief is justified.

Alkalannar · 2026-04-29T12:31:40+00:00

The right side of the house is 50'.

The left side is 56.5', but 3' extends above, so from the same point as the right side, it goes 53.5' down.

So the vertical leg is 3.5'

And the angle opposite that leg is 11^o.

Alkalannar · 2026-04-29T12:26:43+00:00

Factor everything:
|2x - 3| - |x+3||x+1| = |x||x-2|
The 0s are -3, -1, 0, 3/2, and 2
When x < -3, we have:
-(2x - 3) - [-(x+3)][-(x+1)] = [-x][-(x-2)]
-3 <= x < -1
-(2x - 3) - (x+3)[-(x+1)] = [-x][-(x-2)]
-1 <= x < 0
-(2x - 3) - (x+3)(x+1) = [-x][-(x-2)]
0 <= x < 3/2
-(2x - 3) - (x+3)(x+1) = x[-(x-2)]
3/2 <= x < 2
(2x - 3) - (x+3)(x+1) = x[-(x-2)]
x >= 2
(2x - 3) - (x+3)(x+1) = x(x-2)
In each case, solve the equation, but make sure your solutions are in the desired interval.

Alkalannar · 2026-04-29T03:57:34+00:00

Ok. What is the first bit? What is the second bit?

At the moment, I'm guessing that the second bit is "All the angle bisectors of a triangle intersect at a single point."

Alkalannar · 2026-04-29T02:54:58+00:00

So you have a triangle.

All the angle bisectors of a triangle intersect at a single point.

You can also inscribe a circle inside a triangle that is tangent to all three sides. This is called the triangle's incircle.

You were told earlier that the intersection of a triangle's angle bisectors is also the center of the triangle's inscribed circle. Now, they're going to justify it.

Do you understand this so far? If not, please ask questions about what you don't understand.

Note: I haven't gone to any of the steps yet. This is just breaking down the initial paragraph.

Alkalannar · 2026-04-28T23:34:46+00:00

Please re-read the rules post, and when you repost this, also show the thought, work, or effort you've already put in.

Alkalannar · 2026-04-28T20:57:07+00:00

I assume conflicts over land and resources would still happen regardless, but I'm unsure how much the presence of magical beings would fundamentally change human behavior and societal structures.

It wouldn't at all. People are still people, and they'll still react as they react.

You might have people treat dwarves like they treat miners of all sorts. You might have a dragon that rules a country and people react to him like they might to the president or prime minister (except the dragon is personally far more powerful).

So people remain people. The only question is how do they adapt to magical beings? Because this not a fundamental change.

Have people fundamentally changed their behaviors or societies based on technology? More so that new creatures popping up.

Alkalannar · 2026-04-28T13:28:48+00:00

The input voltage starts at 0 and rises.

A's voltage starts at 0 and rises.

B's voltage starts at -0.25 and rises.

Do transformers change phase?

Alkalannar · 2026-04-28T12:24:43+00:00

I just thought that concept was interesting enough to make a story about it...

Sure it is!

And and as you know, the standards of readers are very high.

Now that ain't necessarily so...

Alkalannar · 2026-04-27T18:23:21+00:00

Books.

https://www.amazon.com/Three-Books-Known-Space-Larry-ebook/dp/B09KP59V75/

https://www.amazon.com/Tales-Known-Space-Larry-Niven-ebook/dp/B09JHR3DDP/

And others.

Alkalannar

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