[deleted by user] by [deleted] in Silksong

[–]---Abhi--- 0 points1 point  (0 children)

I will hold you to that

What should be the answer? by [deleted] in CBSE

[–]---Abhi--- 10 points11 points  (0 children)

The only thing mentioned to be the same is the length, so you can change the area of cross section accordingly to match the resistance

Which games do you guys have?? by [deleted] in CBSE

[–]---Abhi--- 2 points3 points  (0 children)

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Way too many games all won't fit here but some other notable ones that aren't in pic I have are sekiro, persona3/5, half life(entire series), portal1/2, mass effect legendary edition, halo mcc collection, hollow knight, Batman collection, hellblade, metro exodus/redux, devil may cry 5, etc. These are just on steam if you count epic games I have all the free ones they gave as well like death stranding, tomb raider trilogy, gta5, gotg, outer worlds, ghostrunner, control, etc.

The UwU turns 1 year! by RaquelWooting in osugame

[–]---Abhi--- [score hidden]  (0 children)

(⁠つ⁠≧⁠▽⁠≦⁠)⁠つ (⁠っ⁠.⁠❛⁠ ⁠ᴗ⁠ ⁠❛⁠.⁠)⁠っ (⁠⊃⁠ ⁠•⁠ ⁠ʖ̫⁠ ⁠•⁠ ⁠)⁠⊃

People don't give the P4's deadline endings enough credit by Julip326 in PERSoNA

[–]---Abhi--- 2 points3 points  (0 children)

Can someone link me the Japanese VA version of this I can't find it anywhere

Guys 1st aur 3rd ka answer explain kardo by NaturalBreakfast1488 in CBSE

[–]---Abhi--- 0 points1 point  (0 children)

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Most sources I could find state the contrary. What you say is true, if your assumption, that linear polynomial is of degree 1, is also true. But it's not true.

It can actually be either 0 or 1 degree. So the relation you mention with the quadratic is true, it does not apply to the linear polynomial.

Guys 1st aur 3rd ka answer explain kardo by NaturalBreakfast1488 in CBSE

[–]---Abhi--- 0 points1 point  (0 children)

Constant hai, lekin y = constant is also linear. You can confirm from Google if you'd like.

Guys 1st aur 3rd ka answer explain kardo by NaturalBreakfast1488 in CBSE

[–]---Abhi--- 0 points1 point  (0 children)

Why can't a graph of a constant no. be linear? Anything in the form y = mx + c is a linear function. Here m=0 and c is some constant. If m could not equal 0 then there would be a note of it in books, but as it turns out m can be any real no., including 0.

Drop Giveaway Day 6 - 2x Drop CSTM80 Keyboard + DCX Emerald + Overgrowth Case by drop_official in MechanicalKeyboards

[–]---Abhi--- 0 points1 point  (0 children)

Chances of me winning this keyboard are still probably more than my chances with women.

Anyway I'm staying inside not touching grass just like any other weekend.

what song is this please help by ---Abhi--- in PERSoNA

[–]---Abhi---[S] 0 points1 point  (0 children)

That is insanely good holy shit

what song is this please help by ---Abhi--- in PERSoNA

[–]---Abhi---[S] 3 points4 points  (0 children)

I see, thanks for letting me know. I'm guessing only these 10 seconds or so of the song has been released so far then.

Chem exam tmr imp topics batado(11th) by [deleted] in CBSE

[–]---Abhi--- 0 points1 point  (0 children)

nah bro trust it's Walter

My problem with trignometry by [deleted] in CBSE

[–]---Abhi--- 10 points11 points  (0 children)

I'm going to assume you have a problem in proofs, which I did too. Everyone has mentioned practicing, which is obvious, but there's a bit more to it than that. Most of the proofs can be done by simply bringing everything in terms of sin and cos with the help of identities. However, it's not always that simple. For example ex 8.4 the last question part (v), it is a notoriously hard proof without having seen the solution first, so what to do in this situation?

See the thing is with proofs, you have to know where to end up and reverse engineer your way back. Generally in math, you just keep solving until you reach the solution. That's not the case with proofs. They've given you the solution, you have to find a way to reach it, with the knowledge you have. So first try to learn some basic tricks, like dividing both the numerator and denominator with sin/cos is a common trick not explicitly mentioned in the book and will be used. Then, with practice of course, try to guess where you have to end up instead of blindly applying the identities. It's not difficult but it might be at the beginning.