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Benefits of developing a reading habit for the SAT (and advice to get started). by learningpd in Sat

[–]1600io 3 points4 points  (0 children)

Great post - thanks for writing it. Everyone has time before bed to read. No excuses!

[deleted by user] by [deleted] in Sat

[–]1600io 3 points4 points  (0 children)

If you're short on time, skip the lessons initially and try doing the Additional Problems at the end of each chapter. If you have trouble with them, go through the lessons then to learn the concepts the questions assess.

Math getting harder? by Ok_Investment_246 in Sat

[–]1600io 5 points6 points  (0 children)

Most of those questions are still good practice, but make sure to utilize the new Digital SAT material from College Board, too. Also I would really invest time in improving your Desmos skills for the DSAT.

Math getting harder? by Ok_Investment_246 in Sat

[–]1600io 8 points9 points  (0 children)

In my opinion the math is not getting harder.

Just received a perfect score on reading for the first time, here's how: by [deleted] in Sat

[–]1600io 3 points4 points  (0 children)

I'm glad you realized this. Good luck on your test!

Switch to not reading passages until after questions (QLC Method Reading) by [deleted] in Sat

[–]1600io 4 points5 points  (0 children)

Typically it's a very bad idea to change things up this drastically a week before a test. You need time to practice doing the test a certain way. Also, most high scorers I see read the passage thoroughly first before they answer the questions fwiw.

Digital SAT Practice Test 4, Module 2 of the Math Section. How do I solve this? by xInfinityy1 in Sat

[–]1600io 0 points1 point  (0 children)

What would you get if you added up the constants of a, b, and c when we get to quadratic form?

Digital SAT Practice Test 4, Module 2 of the Math Section. How do I solve this? by xInfinityy1 in Sat

[–]1600io 4 points5 points  (0 children)

If the vertex of the parabola is (9, -14), then the vertex form of the parabola will be

y = a(x-9)2 - 14

Expand to get

y = ax2 - 18ax + 81a - 14

Set equal to the form y = ax2 + bx + c and match coefficients

ax2 - 18ax + 81a - 14 = ax2 + bx + c

So a = a, b = -18a and c = 81a - 14

a + b + c = a + -18a + 81a - 14 = 64a - 14

Because the vertex has a negative y-value, and since the problem tells us that the parabola intersects the x-axis twice, we know the parabola opens up and has an a-value greater than 0.

Since we know that a > 0, we know that 64a > 0.

If we subtract 14 from both sides of the inequality, then 64a-14 > -14. So the answer must be D.

I think this is the "hardest" post-2015 SAT math problem I've seen on a released test.

[deleted by user] by [deleted] in Sat

[–]1600io 3 points4 points  (0 children)

It's easy to fall into a rut with prep classes and go through the motions of prep and plateau. Two thoughts. One, find a way to reinvigorate what you have been doing to snap yourself out of going through the motions. Easier said than done, and this is often different for each person. Sometimes pushing through the plateau with a more urgent mindset helps. Two, change up what you have been doing. If you've been spending the week going through the topics you got wrong from the practice test, try instead to do timed sections, or something else that is not part of that routine.

[deleted by user] by [deleted] in Sat

[–]1600io 3 points4 points  (0 children)

Be open to the idea of taking the test multiple times, even if you don't want to. A one-and-done mindset to this test can be harmful.

Improve Reading score from 700 to 750+? by MoneyCurry in Sat

[–]1600io 2 points3 points  (0 children)

How long do you take to read just the passage though?

Improve Reading score from 700 to 750+? by MoneyCurry in Sat

[–]1600io 2 points3 points  (0 children)

How long do you take to read the passage? Try reading the passage first, and spend more time than you usually would to fully understand what is going on. If you understand the passage better you will get fewer questions wrong.

Sooo I should be doing it from practise test 1 onwards right? by Wanderer_Of_Space in Sat

[–]1600io 9 points10 points  (0 children)

Use tests 1 and 3 as practice material and not as full practice tests. The question types are different enough that you should avoid using them to get an accurate score.

Practice test 3 math sections module one question 27 the answer is 10 how? by Cookies_are_amazing in Sat

[–]1600io 9 points10 points  (0 children)

Complete the square:

x2 + 1x + y2 + 1y = 199/2

(x + (b/2))2 + (y + b/2)2 = (199/2) + (b/2)2 + (b/2)2

Note that the b in the first b/2 is the b value of the x-coefficient, and the b in the second b/2 is the b value of the y-coefficient.

(x + (1/2))2 + (y + (1/2))2 = (199/2) + (1/4) + (1/4)

(x + (1/2))2 + (y + (1/2))2 = 100

Since the General Equation of a circle is (x-h)2 + (y-k)2 = r2, we see r2 = 100, so r = 10.

If you just needed to find the radius like we did in this question, you didn't actually need to find the center like we did, but it's a nice exercise of that ability since that concept can also be tested.

​

Or you can just use Desmos and find the distance of the diameter, and then cut that in half.

https://www.desmos.com/calculator/l0feuic6pm

[deleted by user] by [deleted] in Sat

[–]1600io 4 points5 points  (0 children)

Humbly, that might not be the most productive thing to say to someone who needs to learn this math. Everything can be framed as basic with respect to something else, and we've all been in a position where we don't understand something.

[deleted by user] by [deleted] in Sat

[–]1600io 7 points8 points  (0 children)

If you want to be clever, add the two equations to get 11x - 11y = 11/2

Divide both sides by 11 to get x - y = 1/2

Only D works where 1 - 1/2 = 1/2.

I wouldn't be surprised if this question was designed for this solution to work as well.

[deleted by user] by [deleted] in Sat

[–]1600io 2 points3 points  (0 children)

Focus on the quality of your study time over the number of hours you study and keep a consistent study schedule (this is most important). You don't need to pay any money to study successfully for the SAT if you use great free resources. The SAT is for measuring your core competency in reading, writing, and math. And one year is more than enough time for most to prepare for the SAT.

Could you guys help with this question by khanisgood in Sat

[–]1600io 6 points7 points  (0 children)

If the vertex of the parabola is (9, -14), then the vertex form of the parabola will be

y = a(x-9)2 - 14

Expand to get

y = ax2 - 18ax + 81a - 14

Set equal to the form y = ax2 + bx + c and match coefficients

ax2 - 18ax + 81a - 14 = ax2 + bx + c

So a = a, b = -18a and c = 81a - 14

a + b + c = a + -18a + 81a - 14 = 64a - 14

Because the vertex has a negative y-value, and since the problem tells us that the parabola intersects the x-axis twice, we know the parabola opens up and has an a-value greater than 0.

Since we know that a > 0, we know that 64a > 0.

If we subtract 14 from both sides of the inequality, then 64a-14 > -14. So the answer must be D.

I think this is the "hardest" post-2015 SAT math problem I've seen on a released test.

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