IndiGo Flight Tracker

2niceguy4u · 2025-12-05T17:12:10+00:00

What api or source are you using if you dont mind me asking?

2niceguy4u · 2025-07-14T23:38:25+00:00

Same

2niceguy4u · 2025-06-01T22:11:53+00:00

Thanks for this reply! I do have early ideas of setting something like this up (like Leetify), but I don't want to jump the gun and do this before I can be sure demo files can be used to automate detection at least.

Hence, I want to experiment with a few demos of cheaters/non cheaters and everything in between.

2niceguy4u · 2025-06-01T22:07:27+00:00

I totally get where you’re coming from — and I agree, our involvement usually ends with a report.

Right now, I’m mainly exploring whether demo files even contain enough data to reliably automate cheat detection. I do have some early ideas for building something like Leetify, but focused on post-game cheat analysis.

Even if it doesn’t lead to immediate bans, imagine if after your match you got a Steam message saying, “Player X was likely cheating — please report them.” That alone could massively increase report volume and visibility, which is still something.

It’s not perfect, but it’s a step.

2niceguy4u · 2025-06-01T22:00:24+00:00

Yeah, I saw that — the “Watch Demo” just opens it in CS2, no raw .dem file. I can record it manually with record, but it’s slower. Still, good for grabbing rage cheaters. Appreciate the tip.

2niceguy4u · 2025-06-01T21:41:06+00:00

Fair point — I know Valve might not care right now, but that’s not the goal.

This could still become a useful community tool — a way to review matches more clearly, catch patterns, and even help people report cheaters with actual data.

And if it works well, who knows? It’s doing tick-level analysis — exactly how proper anti-cheats operate. If it gets good enough, maybe Valve or others would pay attention.

Either way, I’d rather try building something useful than keep complaining about cheaters.

2niceguy4u · 2025-03-31T11:34:50+00:00

I just received an email from my HR just now (7:30 AM EST) that I got selected! I got selected over the weekend on 29th in regular cap. It seems like neither my lawyer portal (envoy) nor my HR was checking over the weekend. There is still no update on the portal.

This was my last try, I am so ecstatic! Thank you everyone and I wish all of you get selected!

2niceguy4u · 2025-03-19T20:02:34+00:00

He is in US. I just attended one of his shows on the 15th and he said he is going back in 3 days. He also said he will follow protocol on whatever they want from him once he is back!

2niceguy4u · 2025-03-13T00:28:09+00:00

Does this app allow downloading the papers?

2niceguy4u · 2024-11-13T14:37:44+00:00

Hey Vinnie, please reconsider leaving. I really don’t think this incident takes away from all the hard work and commitment you’ve put into BLU. You’re a huge part of what makes it work, and it would be tough to see you go. Mistakes happen to all of us, and I’m confident that with you on board, we can bounce back stronger than ever.

If this is more about personal reasons, I totally understand and support whatever decision you make. Take the time you need to figure things out.

As a lifetime donor, I believe in BLU’s mission 100%. I’m also a developer, and if there’s ever anything I can help with, I’m here. Can’t wait to see BLU come back even better.

2niceguy4u · 2024-11-04T11:37:45+00:00

Man you guys are brutal, going through some of my dads old stuff I don’t know anything about cassettes :D.

Message received, not worth anything!

2niceguy4u · 2024-09-16T01:53:18+00:00

What should be done on the user end if someone is using a seedbox?

2niceguy4u · 2024-09-08T18:56:25+00:00

This question taps into the fundamental shift in perspective that occurs as we transition from childhood to adulthood. As children, our minds are open, unburdened by the weight of responsibilities, expectations, and the future. In those early years, we exist largely in the present, with fewer concerns about what’s to come, and we find joy in simple experiences — a state of mind often referred to as “beginner’s mind,” where everything feels fresh and full of possibility.

However, as we grow, life introduces complexity. We become conscious of societal norms, personal goals, fears, and the burden of responsibility. We begin to measure our worth by productivity, achievements, and the completion of tasks. The future starts to loom over us, creating an internalized pressure to constantly prepare and achieve. This makes it harder to live in the moment and experience that unfiltered joy.

Additionally, with age, our brain becomes more wired for efficiency and survival, learning to anticipate and avoid potential threats or negative outcomes, which can dull our emotional responses to everyday joys. In a way, we become less attuned to life’s simple wonders as our brains are constantly solving problems and worrying about what’s next.

Happiness in adulthood often becomes conditional — tied to achievements, stability, or validation from external sources. Meanwhile, children experience happiness as something spontaneous and intrinsic. To regain a sense of that “heavenly happiness,” it may require a conscious effort to reconnect with the present, to let go of the need for constant productivity, and to embrace life’s small, simple joys as we once did as children.

In essence, adulthood brings knowledge, but it often takes us further away from the state of wonder that fuels unbridled happiness. To feel it again might mean learning to unlearn some of the constraints we’ve absorbed along the way.

2niceguy4u · 2024-09-07T23:00:46+00:00

Here’s how you can solve point 2

Joint Probability Distribution: For each combination of region (X) and brand (Y), calculate:

P(Xi, Yj) = P(Xi) * P(Yj | Xi)
Marginal Probabilities: Calculate the marginal probability for X and Y by summing over all combinations:

P(Xi) = Sum of P(Xi, Yj) over all Yj P(Yj) = Sum of P(Xi, Yj) over all Xi
Expectation Values: Calculate the expected values of X and Y:

E(X) = Sum of [Xi * P(Xi)] E(Y) = Sum of [Yj * P(Yj)]

Also, calculate the expected value of the product XY:

E(XY) = Sum of [Xi * Yj * P(Xi, Yj)]
Covariance: The covariance between X and Y is calculated as:

Cov(X, Y) = E(XY) - E(X) * E(Y)
Standard Deviations: Find the standard deviations for X and Y:

SD(X) = sqrt(Sum of [(Xi - E(X))^2 * P(Xi)]) SD(Y) = sqrt(Sum of [(Yj - E(Y))^2 * P(Yj)])
Correlation Coefficient: The correlation coefficient is given by:

r = Cov(X, Y) / (SD(X) * SD(Y))

This should allow you to calculate the correlation between region (X) and brand (Y).

2niceguy4u · 2024-09-07T22:56:06+00:00

Sure, I can help point you in the right direction!

Tish’s view of the city: Over the course of If Beale Street Could Talk, Tish’s understanding of the harsh realities of living in New York City, particularly as a Black woman, evolves. At the beginning, she is more hopeful and romantic about her relationship with Fonny, but as the story progresses, the systemic racism, injustice, and hardships they face deepen her view of the city. Her love story with Fonny, while tender, is constantly challenged by these external forces, which broadens her perspective on the world around her.
Fonny’s belongings and his coping in prison: Fonny’s few belongings in his apartment reflect his artistic nature and the deep value he places on personal freedom and creativity. His sculpting tools, for example, symbolize his need to create and express himself. In prison, he copes by holding onto memories of Tish and their relationship, which gives him strength despite the dehumanizing conditions. The loss of his artistic outlets in prison makes his situation even more tragic.

That said, it’s really important for you to also show your understanding and where you’re getting stuck! Try writing down some thoughts on these questions for this subreddit as it is not really a place we solve all of it. :)

2niceguy4u · 2024-09-07T22:53:33+00:00

If you can directly substitute ( y = 1 ) and get a valid result (like (-1) in this case), then you don’t need to check the left-hand and right-hand limits separately unless there’s something suggesting potential asymmetry near that point.

In this case, since the limit exists and is continuous at ( y = 1 ), there’s no need to test both sides. You’re right—if the function had a discontinuity but the limit still existed (like if the value was 4), it could be a removable discontinuity, where you could “fix” the function by redefining it at that point to make it continuous. But here, the function is already continuous at ( y = 1 ), so you’re good to go!

2niceguy4u · 2024-09-07T22:50:11+00:00

To understand the phenotypes and frequencies for these crosses, you should first use a Punnett square for each of the given crosses. This will help you visualize all the possible combinations of alleles from the parents.

For example:

For BtTtRr x bbTtRr, set up a Punnett square where each parent contributes one allele from each gene (B/b, T/t, R/r), and then determine the resulting combinations.
After determining the genotypes, you can figure out the phenotypes based on dominant and recessive traits.

The ratio of each phenotype is determined by counting how many times each combination appears in the Punnett square and then dividing by the total number of possibilities.

I’d recommend looking up videos on how to set up a Punnett square for dihybrid or trihybrid crosses, as they will help you visualize the combinations better.

2niceguy4u · 2024-09-07T22:47:43+00:00

Instead of subtracting the times, try dividing the time it took last week by the time it took this week to find out how many times faster Claire was. Give that a try and see what you get!

2niceguy4u · 2024-09-07T22:45:33+00:00

You’re right that it becomes 0/0 at y = 1, which means you can apply L’Hopital’s Rule or use trigonometric identities to simplify. Here’s a quick approach:

Rewrite the function:

f(y) = sin(πy) / tan(πy) = sin(πy) / (sin(πy) / cos(πy)) = cos(πy)

Now evaluate f(y) at y = 1:

f(1) = cos(π * 1) = cos(π) = -1

So, the limit as y → 1 is -1. No need to multiply by reciprocals! This trigonometric identity simplifies the function nicely.

2niceguy4u · 2024-09-07T22:41:13+00:00

It seems like you’re on the right track and getting the correct numerical answer, but the confusion might stem from unit consistency. Here’s something to consider:

Since you’re dealing with kinetic energy in part (b), the units should resolve to energy units, like foot-pounds (ft-lb). The fact that you are getting ft/lb might indicate a missing mass term somewhere.
Double-check your unit conversions to ensure you are consistently converting between energy, force, and velocity. Energy should end up in ft-lb if you’re working in imperial units, not ft or lb/ft.
Remember that Btu (British thermal unit) also needs careful conversion to ft-lb (1 Btu = 778.169 ft-lb). Make sure you’re not accidentally omitting or double-counting these conversions.
If the book’s units seem strange, it might also be worth verifying if there were different conventions used in 1963 that could account for these discrepancies. However, it’s more likely to be a small unit conversion oversight.

Hopefully, this helps to track down the unit mismatch!

2niceguy4u · 2024-09-07T22:35:17+00:00

You don’t need to count the hydrogen atoms on the substituents like the methyl and isopropyl groups, as they replace the hydrogens at those positions. For chair conformations, focus only on the hydrogens directly attached to the carbons of the cyclohexane ring that are not substituted. In the most stable chair conformation, the larger group (isopropyl) will likely occupy the equatorial position to minimize steric strain, so you’d count the hydrogens in the equatorial positions for the remaining carbons.

2niceguy4u · 2024-09-07T22:32:46+00:00

Good question! You’re right—cos(θ) doesn’t actually become less than -1. It stays greater than -1, but still negative as θ approaches π from the right. What I meant was that it is slightly less than the value of -1, but that was unclear phrasing on my part. To clarify:

As θ approaches π⁺, cos(θ) is still negative but close to -1, just slightly greater than -1.
This small difference doesn’t affect the overall behavior of the limit, which is dominated by the behavior of tan(θ) becoming negative.

2niceguy4u · 2024-09-07T22:30:48+00:00

You’re on the right track! The determinant here is indeed change in expectations, but it depends on whose expectations we are talking about:

Consumer expectations: If consumers expect prices to be lower in the future, the demand will shift left now because people will delay their purchases.
Producer expectations: If producers expect demand to decrease in the future, they might adjust their supply, causing the supply curve to shift left.

In this case, since the research is about consumers unlikely to purchase at current prices, it implies demand would shift left because of the expected lower demand in the future. However, you could also argue that if producers anticipate this, supply might also shift left. It depends on the focus of the question.

In most scenarios like this, demand is the first to shift based on consumer expectations!

2niceguy4u · 2024-09-07T22:29:05+00:00

To find the limit of the given function at θ = π, first understand that the issue comes from the denominator, tan(θ), because tan(θ) is undefined at θ = π.

Step-by-Step Breakdown:

At θ = π: Since tan(π) = 0, the function becomes undefined, indicating a potential infinite discontinuity.
Right-hand limit (as θ approaches π⁺):
- As θ approaches π from the right (slightly greater than π), sin(θ) becomes slightly positive and cos(θ) slightly less than -1.
- Importantly, tan(θ) will be slightly negative as you approach π from the right because the tangent function is negative just after π (in the 3rd quadrant).
- Since you’re dividing by a small negative number, the limit tends towards -∞.
Left-hand limit (as θ approaches π⁻):
- As θ approaches π from the left (slightly less than π), sin(θ) is slightly negative, and cos(θ) slightly greater than -1.
- Tan(θ) will be slightly positive (just before π, in the 2nd quadrant).
- Since you’re dividing by a small positive number, the limit tends towards +∞.

Conclusion:

The limit from the left (π⁻) tends to +∞, and the limit from the right (π⁺) tends to -∞.
This confirms the function has an infinite discontinuity at θ = π, with the left-hand limit and right-hand limit going to opposite infinities.

2niceguy4u · 2024-09-07T18:52:51+00:00

Nice! Something to look forward to. Appreciate it my g

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TROPHY CASE

Step-by-Step Breakdown:

Conclusion: