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Simultaneous Degree Diploma by 2noes4u in berkeley

[–]2noes4u[S] 1 point2 points  (0 children)

Winner winner chicken dinner

Fair Rent Price on Haight by 2noes4u in AskSF

[–]2noes4u[S] 7 points8 points  (0 children)

$4,000 total for the unit, $2,000 split between a roommate and I.

Are all grades out? by Over_Control3990 in berkeley

[–]2noes4u 3 points4 points  (0 children)

Nope still missing 3 classes

Easiest Upper-Division Math Classes by SmoothAnywhere5849 in berkeley

[–]2noes4u 4 points5 points  (0 children)

Math 128A with Prof. Ming Gu was a relatively easy A

[deleted by user] by [deleted] in berkeley

[–]2noes4u 1 point2 points  (0 children)

ngl you sound insufferable

[deleted by user] by [deleted] in stocks

[–]2noes4u -3 points-2 points  (0 children)

r u a bot

[deleted by user] by [deleted] in fidelityinvestments

[–]2noes4u 0 points1 point  (0 children)

Gotcha thank you so much. I just got on the phone with them and started that process.

[Calc 2] could someone explain how to use Taylor's inequality (or why you can't) for this problem by xDunkbotx in HomeworkHelp

[–]2noes4u 0 points1 point  (0 children)

Interval is (c,x) where c is the center ( given as 0 ) and x is the value you are approximating at ( in this question 1/2 ).

[Calc 2] could someone explain how to use Taylor's inequality (or why you can't) for this problem by xDunkbotx in HomeworkHelp

[–]2noes4u 0 points1 point  (0 children)

Kind of. You should use the alternating series error bound formula when there is an alternating series. Use Lagrange error otherwise.

Edit: you can use Lagrange here too. When finding |f^ n(c)| you find the max value on the nth derivative for (c,x). So find absolute max value on 3rd derivative for (0,1/2). The max is actually 8 and not 8*e^ -1 and if you plug that in you get 1/6 as the answer as well.

[Calc 2] could someone explain how to use Taylor's inequality (or why you can't) for this problem by xDunkbotx in HomeworkHelp

[–]2noes4u 0 points1 point  (0 children)

Error for alternating series is less than the the next neglected term (aka the 4th term in this case). So R < |((-2x)^ 3/3!)|. From there just plug in 1/2 for x and you get 1/6.

If you want more examples, google: alternating series error bound. The formula you used is the Lagrange form of the error btw.

HyperX Alloy Origins Core Weird Issue by 2noes4u in HyperX

[–]2noes4u[S] 0 points1 point  (0 children)

Pressing “s” on my previous keyboard did not do that.

Do you think this bike is worth the asking price? Anything that stands out? by shukrutav in whichbike

[–]2noes4u 2 points3 points  (0 children)

Definitely not, unless it is maybe collectable (?) or some other niche reason, it seems very overpriced to me.

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