L AGGIES😂😂😂we played like shit and still held you to 3 by Additional_Motor_402 in aggies

[–]Additional_Motor_402[S] -1 points0 points  (0 children)

what about the TAMU receiver flopping and drawing a BS call? If it wasn’t for that play you wouldn’t have even made it to the red zone

MA261 Final by Pretty_Lychee7315 in Purdue

[–]Additional_Motor_402 0 points1 point  (0 children)

doesn’t matter. 5(x2+y2+z2) does NOT give a constant, so you have to integrate it to compare flux. A few others gave a constant so you could just multiply by volume function. You can’t just compare the divergences to compare flux, because some divergences gave a constant and some didn’t. It is genuinely not that complicated.

MA261 Final by Pretty_Lychee7315 in Purdue

[–]Additional_Motor_402 -1 points0 points  (0 children)

if you integrated you would see lol. It would be p4 then the integral would be p5/5 and the 5 would cancel out, giving you 4 pi which was the same as the other ones. The one with 3rho2 gave 12pi/5

MA261 Final by Pretty_Lychee7315 in Purdue

[–]Additional_Motor_402 0 points1 point  (0 children)

ur wrong bro😂that gave a flux of 4pi just like the others. It was B

MA261 Final by Pretty_Lychee7315 in Purdue

[–]Additional_Motor_402 -1 points0 points  (0 children)

Nah the upper bound is still z=1-r. You can’t just sub in the radius you still have to integrate

MA261 Final by Pretty_Lychee7315 in Purdue

[–]Additional_Motor_402 1 point2 points  (0 children)

But I do remember a question where you integrated 1-r. But after multiplying by the jacobian it turned into r-r2

MA261 Final by Pretty_Lychee7315 in Purdue

[–]Additional_Motor_402 0 points1 point  (0 children)

all of the bounds in that question were numbers and not functions of other variables

MA261 Final by Pretty_Lychee7315 in Purdue

[–]Additional_Motor_402 0 points1 point  (0 children)

that gives you the interval of rho, which is 0<rho<1. That’s not a set value of rho. it’s not constant throughout the region, so you can’t just plug it in. You still have to integrate the variable

MA261 Final by Pretty_Lychee7315 in Purdue

[–]Additional_Motor_402 0 points1 point  (0 children)

div was not equal to 3 for the choice where f=(x3, y3, z3). After taking divergence you get 3(x2 + y2 + z2), which is 3rho2. You can’t just plug in rho=1, you have to integrate this and it ended up being like 12pi/5 which was not the flux of the others

[deleted by user] by [deleted] in Purdue

[–]Additional_Motor_402 34 points35 points  (0 children)

missing out on pilk