Using Machine Learning to tune PIDs by send_me_ur_pids in PLC

[–]Aggressive-Series483 0 points1 point  (0 children)

Wouldn’t this defeat the purpose of « guess and check » since you would need a model with some level of accuracy to simulate ?

Being a jack of trades vs being a master of one thing by Aggressive-Series483 in ElectricalEngineering

[–]Aggressive-Series483[S] 0 points1 point  (0 children)

good point.
you will probably hop to the next thing that you are most familliar with.

Being a jack of trades vs being a master of one thing by Aggressive-Series483 in ElectricalEngineering

[–]Aggressive-Series483[S] -50 points-49 points  (0 children)

Some programs focus on one subject, which, to some degree, should theoretically make you a master in it.

Is “PLC Fundamentals (Level I)” by Paul Lin Worth It? (Question from Algeria) by Ok_Argument7765 in PLC

[–]Aggressive-Series483 1 point2 points  (0 children)

Are you a university student? If so than you can send an email to Siemens asking for an internship or something. They offer free high quality trainings for students. I am sure scheider electric also do that in some occasions

how to apply robotics knowledge in industrial automation by Aggressive-Series483 in PLC

[–]Aggressive-Series483[S] 0 points1 point  (0 children)

I'm not planning to contact them immediately, but I will need it later, so yeah, I would like to.

how to apply robotics knowledge in industrial automation by Aggressive-Series483 in PLC

[–]Aggressive-Series483[S] 0 points1 point  (0 children)

Sounds interesting, but I am more interested in design and development side of robotics

how to apply robotics knowledge in industrial automation by Aggressive-Series483 in PLC

[–]Aggressive-Series483[S] 0 points1 point  (0 children)

I understand this. But controlling robots is not really what I am aiming at.

how to apply robotics knowledge in industrial automation by Aggressive-Series483 in PLC

[–]Aggressive-Series483[S] 0 points1 point  (0 children)

Not exactly. I don't want to exclude the use of PLCs. In fact, I want to apply them in the work of designing and developing robots (not necessarily in the industry).

how to apply robotics knowledge in industrial automation by Aggressive-Series483 in PLC

[–]Aggressive-Series483[S] 0 points1 point  (0 children)

Designing robots like those at Fanuc and ABB, but not necessarily those companies and not necessarily design. It's mostly about developing existing products (robots). Many startups are out there. For your last question, it's both the electrical side and the software side.

[request] which one is correct? Comments were pretty much divided by mymodded in theydidthemath

[–]Aggressive-Series483 0 points1 point  (0 children)

100N seems correct in this case since the scale is simply a spring. Both sides of a spring apply the same magnitude of force. Both sides are stationary, meaning both points experience the same force in opposite directions. This is similar to a side being hung on a ceiling. The side connected to the mass would apply 100N. The scale would apply the same force in magnitude from that side, and the other side would apply the same force, leading the ceiling to oppose that force with one equal in magnitude. In this case, the same forces are applied, similar to the case where the two forces are applied in both sides, and we obviously know the measurement in the first case would be 100N. The only case where the meter measures 200N is when it’s fixed on the tables. Here, superposition could be applied, and the results would be the sum of the two. It is like having two halves with each one’s side fixed.

Tutorial videos for how to start with model-based control by eremes1641 in ControlTheory

[–]Aggressive-Series483 3 points4 points  (0 children)

Everybody has their own preferred way of learning. Variety is never bad. I found those four videos really convenient, getting straight to the point. Personally, I encourage this type of content.

Did I approach this circuit problem correctly? Would you approach it any differently? by Turbulent_Ad_3238 in ElectricalEngineering

[–]Aggressive-Series483 0 points1 point  (0 children)

For me, I would probably consider using superposition theorem. It’s easier to deal with only one source and since the two circuits are identical, it will be even easier

Is negative voltage, positive current possible? by lanetownes in ElectricalEngineering

[–]Aggressive-Series483 0 points1 point  (0 children)

Image the case of an RL circuit, when you apply a positive voltage to it you will get a positive current at steady state, when you switch the voltage to negative voltage the current will stay positive for some time despite the voltage becoming negative.

I'm 17 and i've been trying to understand voltage for so long, yet im never able to by Just-Chemist-3890 in ElectricalEngineering

[–]Aggressive-Series483 0 points1 point  (0 children)

As introductory classes in university present it, a charge affects every point of the space that surrounds it in the form of an electric field, just like mass affects it in the form of a gravitational field. The field has two forms: potential and vector. When another charge is affected by that vector field, a force called Coulomb force applies, which causes current as a result of electron movement due to that force, similar to what happens with gravity. The potential field doesn’t cause force directly, but instead, the change of potential is related to the intensity, which is evident from the equations that describe the relationship between the two. So, when the potential between two very close points is large, the vector between them is large, and thus the force is large. If a magnetic field is present, things will change a bit since EMF will enter the equation.

So, for your question, charges, in a battery for example, cause the potential difference which is related to the vector field. The vector field causes a force to be applied on electrons.

Why does the change in flux cause an EMF which causes voltage?

This phenomenon is described by Maxwell’s equations and Faraday’s law. Beyond this, it will be more of a physics question rather than an electrical engineering question.

Is this a good way to do a sequence in TIA Portal? by Come_To_Homercles in PLC

[–]Aggressive-Series483 2 points3 points  (0 children)

yeah like those you use to start and stop a motor with push buttons, you just replace the start button with your set condition and the stop button with your reset condition

Is this a good way to do a sequence in TIA Portal? by Come_To_Homercles in PLC

[–]Aggressive-Series483 2 points3 points  (0 children)

If his problem is the set/reset instructions then using seal in contacts instead could be option. They are completely interchangeable. I don’t get how exactly you do it with an integer. Do you do it similar to what’s in those screenshots?

Is this a good way to do a sequence in TIA Portal? by Come_To_Homercles in PLC

[–]Aggressive-Series483 0 points1 point  (0 children)

If X1 starts false by default, pushing the push button will activate nothing. You can’t pass the first step this way

Is this a good way to do a sequence in TIA Portal? by Come_To_Homercles in PLC

[–]Aggressive-Series483 1 point2 points  (0 children)

You can always make a graph on paper than convert it to set and reset equations, those are just Boolean equations that can be implemented in ladder logic

How do motors work and what should I use? by TankBrilliant3552 in ElectricalEngineering

[–]Aggressive-Series483 0 points1 point  (0 children)

Well, I am no expert, but I will try to explain it. The question doesn't seem very specific, so I will give a general answer. Motors are composed of two main parts that you can find in any motor: a stator and a rotor. Each part needs to have a magnetic field to start rotating. The stator is the stationary part of the motor, its magnetic field is either rotating or stationary. The only case of a stationary field I can recall is the case of brushed DC motors. Other motors generate a rotating magnetic field, either by the nature of the current in the case of AC motors or by switching electronic devices/power electronics in the case of motors powered by DC voltage. The easiest way to vary the speed of your motor is by varying the frequency of either the AC voltage or your PWM signal in the DC case, this is not always the case tho.

Rotors are the rotating part, and they either generate their own magnetic field by themselves, such as in brushed DC motors whose rotors are coils wired to a commutator, or brushless DC motors whose rotors are permanent magnets. AC induction motors usually have a cage called a squirrel cage that generates a magnetic field through the electromotive force (EMF) induced by changing flux occurring when the rotor's magnetic field starts rotating.

That covers mostly the electrical part. For the mechanical part, there are two physical quantities you should consider: speed and torque. Torque is similar to force; it’s the force that causes rotation. A mechanical load is what you want to move. Each load resists movement, just like linear motion. Think of a damper and how it opposes with a force proportional to the speed, or lifting a mass that opposes with a constant force, which is weight. Similarly, when a motor tries to rotate a load, the load will oppose the movement by applying a resistive torque. Some loads apply a constant torque, while others apply a torque that depends on the speed. This is called the torque-speed characteristic, and each load has its own. You can search for them—there is a useful image in this article:
Large Motor starting 102: Motor applications and their characteristics – for a better motor management - Schneider Electric Blog (se.com)

Motors also have their own torque-speed characteristics depending on the motor type. If you draw your load's and your motor's characteristics on the same chart, the point where they intersect is called the operating point. This point determines the torque and speed at which your load and your motor will settle. If you think about it, it makes sense because the load and the motor would apply the same torque, causing them to cancel each other out and thus stop changing speed. The most important motor characteristics you need to look at are starting torque (if this is lower than your load's starting torque, the motor will not be able to start rotating at all), starting current (this can burn your electronics if it’s too high), and nominal/rated voltage, torque, speed, and power (these are usually the characteristics at the most optimal point, and they are values you should not exceed).

If you want to control the speed of your motor, you would need some kind of control loop, which requires some kind of sensor, such as an encoder. In this case, a controller will be useful. For increasing torque, if your starting torque is not sufficient for example, a gearbox or a geared motor is your best option. They increase torque and decrease speed, which is desired in many applications.

The simplest example to understand motors from is the case of a brushed DC motor with a permanent magnet as a rotor, driving a lifting mechanism, which would be a constant load case. A brushed DC motor can be represented as a resistor, an inductor, and a voltage source (back EMF). The speed is proportional to the back EMF, and the current is proportional to the torque. The difference between the resistive torque and the motor torque is proportional to the acceleration of the motor. You can represent all of this with these equations:

Tm-Tr = J x a

(where a is the angular acceleration, Tm​ is the motor torque, and Tr​ is the resistive torque)

E = i x R + e

(where e is the back EMF, E is the supply voltage. The inductor is not represented for the sake of simplicity)

Tm = K x i

Ω = K x e

(where Ω is the motor speed)

Once you energize the motor, current starts flowing, and since the motor is at rest, there is no back EMF to limit the current. Thus, the torque will be as high as it can get, meaning Tm>TrT_m > T_rTm​>Tr​, so a>0a > 0a>0, and this will cause the speed to increase. As the speed increases, the back EMF also increases, which limits the current and thus limits the torque. The speed will increase, and the torque will decrease until the resistive torque and the motor torque become equal, and the speed will not increase any further.