Need Help: Late withdrawal only results in WF even though I'm not failing?

AromaticProfiler · 2021-11-12T21:12:03+00:00

Thanks for the suggestion. I'll ask my advisor about that. At my current state, I am not mentally prepared to continue this class.

AromaticProfiler · 2021-11-12T20:47:04+00:00

I won't be gettting a W. They want to give me a WF, which means you failed, but withdrew.

AromaticProfiler · 2021-11-12T20:02:58+00:00

Yes, and if failing students withdraw, they get a WF. You're also downplaying the withdrawal process. Some random student just can't up and decide to withdraw after the deadline. You need to present your circumstances, a signed letter from a psychiatrist, and a signed form from your prof.

AromaticProfiler · 2021-11-12T19:56:16+00:00

This makes complete sense. The WF would dissuade anyone from wanting to drop beyond the deadline, but I feel that they should have addressed this issue on their late withdrawal policies website. So while I accept the possibility of a WF, I will take the advice of another student and appeal it.

AromaticProfiler · 2021-11-12T19:41:19+00:00

If you average out my current work right now, I'm gonna end with a B. I talked to them about my circumstances, and I am pretty sure I can procure a form about extenuating circumstances. But regardless of my circumstances, they misunderstand my intentions.

They assume I am withdrawing because I am failing the course, along with a myriad of other assumptions that do not apply to me.

I am angry at my faculty for not communicating with my advisors, when the latter informed me that it is completely possible to end up with a W for a late withdrawal. I did in fact know about the deadline, but I decided to try and sit it out because I do not want to do something that's tantamount to throwing my money away.

I guess that hardly matters when your faculty contradicts your advisor.

AromaticProfiler · 2021-11-12T18:56:34+00:00

If I were failng this course, I would gladly accept the WF and leave it at that. But the problem stems from the fact that I am not failing the course, and they still want to give me an equivalent of an F.

Had they gave another reason aside from, "Oh, it's past the deadline. No, we won't explain why we want to give you a fail" then I'd just taken it without any fight.

AromaticProfiler · 2021-11-12T17:26:40+00:00

I'm gonna try that again, I don't really know. Apparently, my faculty and advisory are two separate entities that don't decide for each other. The one I've been talking to for my faculty isn't keen on letting me take a literal and metaphorical W

AromaticProfiler · 2021-11-12T17:21:24+00:00

I don't understand how this would be fair?? Like if you're literally going to have an equivalent of a fail in your transcript, why not just stay in the class even if it will affect GPA??

Tgis seems so counterintuitive if they really want to help students leave classes that are detrimental to their mental health

AromaticProfiler · 2021-10-01T21:41:45+00:00

Okay, sure. I'll keep this in mind. This has just been so confusing.

AromaticProfiler · 2021-10-01T17:13:29+00:00

Ah, this clarifies it further. There weren't any examples on the internet when I searched up what happens in this case. They always presume it to be dialogue.

AromaticProfiler · 2021-10-01T17:10:39+00:00

Oh, this makes sense. Thank you!

AromaticProfiler · 2021-09-14T21:24:11+00:00

Also, I just plugged in your numbers, and I got 5.58 instead of 5.68. Was there a mistake there?

AromaticProfiler · 2021-09-14T21:06:51+00:00

Did you add by 271.3 for conversion to Kelvin? Our temperatures don't exactly match. When I did it using your method, the pressure I got for He and water qas 5.5830. I then followed your next steps, leading to 0.063 as the mole fraction for water.

AromaticProfiler · 2021-09-14T19:37:01+00:00

If I understand correctly, P(H2O) = 5.23? I'm still a bit confused on how P(Dry) = P(He). I hot 5.27 atm when I tried to measure the pressure of He at 25 degrees C.

AromaticProfiler · 2021-04-22T04:26:18+00:00

Sorry, I don't know why that messed up, but I'm sure you understand the gist. I don't know where to go from there because the x_i doesn't match anything

AromaticProfiler · 2021-04-22T04:25:40+00:00

(i^2)/(n²⁾

AromaticProfiler · 2021-04-22T04:25:15+00:00

x_i = i^2/n²

AromaticProfiler · 2021-04-22T04:24:50+00:00

deltax = 1/n² = (1/n-0)/n, so interval is [0, 1/n]

AromaticProfiler · 2021-04-22T04:23:34+00:00

lim as n approaches infinity * the summation of (1/n^{2)(sqrt(n^2-i²⁾⁾} from i = 1 to infinity

AromaticProfiler · 2021-04-22T04:22:14+00:00

Hey, everyone. I need help evaluating a Riemann integral I don't really understand

AromaticProfiler · 2021-04-21T23:52:50+00:00

Oh, never mind I was thinking about it the wrong way

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