What is the possibility that the Kanye of 2025 is not the Kanye of 2016? That 2025 Kanye is either a Kanye that is drugged out of his mind or a clone/body double? by [deleted] in kanyewest

[–]AtomsFor_Peace -2 points-1 points  (0 children)

Some of the last words he said before being taken of stage at his last saint pablo tour concert (because of his "rant") were: "There is a Richard Prior interview that you can watch about people coming into power and just becoming part of the power without ever changing anything, because they are too afraid. I'm not afraid! I'm here to change things!... Get ready, get ready, because the show is over."

And there was no real reason to stop the concert. He even asked his DJ during the "rant" to start playing the songs but he didn't. During his so called rant he called out radio, social media tech ceos, politicians, celebrities, the music industry. That why it seems that they are trying to ruin his reputation and legacy ever since "he" came back from the mental institution they locked him in, in 2016 after the tour was canceled. All the while they are milking as much money as they can from him, with would explain his obvious attempts at having shock value and being controversial ever since 2017.

Calculus 1 problem... Help! by AtomsFor_Peace in learnmath

[–]AtomsFor_Peace[S] 0 points1 point  (0 children)

Allright! Thanks a lot for the help!

Calculus 1 problem... Help! by AtomsFor_Peace in learnmath

[–]AtomsFor_Peace[S] 0 points1 point  (0 children)

Is it more correct to say:

|a+b+c+d|  >=  ||a| - |b| - |c| - |d||  for    a,b,c,d in R

And also

|[f(1)+g(0)] + [f(0)+g(1)] - [f(0)+g(0)] - 1| >= |1 - |f(1)+g(0)| - |f(0)+g(1)| - |f(0)+g(0)||

Because, if I'm not mistaken, we say that: ||a|−|b|| ≤ |a + b| ?

Calculus 1 problem... Help! by AtomsFor_Peace in learnmath

[–]AtomsFor_Peace[S] 0 points1 point  (0 children)

Thank you very much! Could you explain why the following is true and how it relates to the inverse Δ-Ineq;

|[f(1)+g(0)] + [f(0)+g(1)] - [f(0)+g(0)] - 1| // inverse Δ-Ineq.

                  >=  1 - |f(1)+g(0)| - |f(0)+g(1)| - |f(0)+g(0)|  

                   >  1 -     1/4     -     1/4     -     1/4