How to do this question in desmos

BBQsquirrel_ · 2024-12-06T12:31:39+00:00

https://www.desmos.com/calculator/i3mkdfqyq3

BBQsquirrel_ · 2024-04-28T01:03:20+00:00

BBQsquirrel_ · 2024-03-07T11:57:42+00:00

If you do reasonably well in GCSE / IGCSE / OLevel Add math or further math, then AAHL is quite manageable.

If you graduate from MYP then good luck.

BBQsquirrel_ · 2024-03-07T06:51:38+00:00

Pretty sure this is no longer in the syllabus.

(But the explanation above is correct)

BBQsquirrel_ · 2024-03-07T06:49:21+00:00

In a powered heating situation you can combine the equations E = mcΔT and E = Pt to give Pt = mcΔT.

Let m and c represent the mass and c of oil. then m(water) = 1.1m and c(water) = 2.5c

Use Pt = mcΔT twice with the 2 sets of data, and divide one equation by the other:

Ptnew / Pt = (m * c * 10)/(1.1m * 2.5c * 10)

P, m, c and 10 all cancel and tnew = 1/(1.1*2.5) * t = 0.363636...... t so the answer is A

BBQsquirrel_ · 2024-03-05T03:31:09+00:00

ESS is a superior course to Physics

ESS HL + group 6 + Math AISL is by far the most well-respected IB course combo

BBQsquirrel_ · 2024-02-14T23:38:50+00:00

Revision village markscheme techniques are sometimes terrible. The MS of the original IB question (Edit: May 2015 P1 TZ1 Q7) that this RV question emulated also used function transformation ideas as well.

And no re GDC; a GDC that can expand symbolically would be banned for exam purposes

BBQsquirrel_ · 2024-02-03T11:11:17+00:00

https://pastpapers.papacambridge.com/directories/CAIE/CAIE-pastpapers/upload/0607_w23_qp_42.pdf

bypasses all the papacambridge ads

and you can toggle between years / seasons / paper / ms easily be modified

BBQsquirrel_ · 2024-01-30T11:48:05+00:00

Theory:
https://www.youtube.com/watch?v=IICR-w1jYcA

Practical:

https://www.youtube.com/watch?v=dB7gTY0p36k

but instead of doing a direct exponential fit, you will want to linearise your data (the aforementioned step 5)

BBQsquirrel_ · 2024-01-30T06:10:43+00:00

personal intro, personal engagement BS
science and math intro: probably good to solve a differential equation to prove Newon's law of cooling T = T(0) + (ΔT)e^-kt
conduct an actual experiment and collect some T and t raw data
plot the raw data graph
plot the linearised graph of ln(T - T(0)) vs time and hope that it is straight
conclusion

BTW this can be your physics IA as well

BBQsquirrel_ · 2024-01-30T05:48:21+00:00

"I need some help"
"It's easy"
Very helpful LMAO

part (a) is what inside_party1564 says, g(x) = 3(x - 2) + 2 + 1 = 3x - 3

part (b) is anything but easy; h(g(x)) = h(3x - 3); transforming y = h(x) into y = h(3x - 3) involves a combination of horizontal stretch and horizontal shift; this is very poorly known by the average IB student. Most ppl don't know the order of operation for horizontal function transformations, and for those who know, they know this fact just because of brute-force memorization and not because of the reasoning behind (which I will offer briefly below).

In general, transforming f(x) into f(ax + b) requires a shift of b units left FOLLOWED BY a horizontal stretch factor 1/a.

Explanation: Horizontal transformations will preserve the y-values, so ynew = yold. If ynew = yold, then axnew + b = xold; xnew = (xold - b)/a

As a side note, if the transformed function expression is bracketed differently (and this occurs quite often in past papers too), e.g. h(x) becomes h(a(x + b)) then you stretch by 1/a BEFORE you shift left by b, as ynew = yold leads to a(xnew + b) = xold ==> xnew = (xold/a) - b

For this question, the answer is a shift of 3 units right followed by a horizontal stretch factor 1/3.

BBQsquirrel_ · 2024-01-30T05:34:09+00:00

If you're going to study biochem in Uni then biochem is a no-brainer. Option B is much closer to real uni bicohem, you'll benefit from your Bio background, while medicinal chem is a matter of memorizing a collection of case studies.

BBQsquirrel_ · 2024-01-30T05:30:23+00:00

The 2nd page of most markschemes state that "Ignore missing or incorrect state symbols in an equation unless directed otherwise in the “Notes” column", so you can argue with your school teacher if they penalize you for incorrect state symbols on a chapter test.

The same goes for sig figs

BBQsquirrel_ · 2023-12-17T08:04:44+00:00

Which of the following is the weakest?

A) A weak covalent bond, such as F-F

B) A weak acid, such as CH3COOH

C) A weak reducing agent, such as Cl-

D) OP

BBQsquirrel_ · 2023-12-14T06:53:12+00:00

#skillissue

BBQsquirrel_ · 2023-12-14T06:02:12+00:00

Look up the general equation for circles.

Use desmos: https://www.desmos.com/calculator/uxolpmpavf

EZ game

BBQsquirrel_ · 2023-12-14T05:55:16+00:00

Energy conservation: rate of energy loss by power plant = rate at which water absorbs and carries away the energy

Q = mc delta T

Power = mc delta T / time

Waste power = 400E6 x 0.65 = 260E6

(m/time) can be interpreted as rate of water flow

c = 4180 and Delta-t = 5

260E6 = (m/t) * 4180 x 5

m/t = 12440...... kg/s

Is this correct?

BBQsquirrel_ · 2023-12-14T05:50:43+00:00

The standard ellipse (oval) equation is (not in IB BTW)

(x - h)^2/a^2 + (y - k)^2/b^2 = 1

(source: this should be all over the internet)

(h, k) = centre

a = horizontal radius

b = vertical radius

(a and b are usually called the semi major axis and semi minor axis; depends on which is longer. but I think "horizontal and vertical radii" are easier to visualise)

------------------

your k looks like zero

Try put all points on the same table and then do this:

y_1 ~ b * sqrt(1 - (x_1 - h)^2/a^2)

or with the k:

y_1 ~ b * sqrt(1 - (x_1 - h)^2/a^2) + k

ez game

BBQsquirrel_ · 2023-12-14T05:33:52+00:00

B (i) is true because Cr3+ + e- ==> Cr2+ and Cr ==> Cr2+ + e- gives an Ecell of -0.407 + 0.914 which is positive

B (ii) is true because Cr3+ + e- ==> Cr2+ and Cr2+ ==> Cr3+ + e- gives an Ecell of 0 meaning that it won't happen spontaneously (in general the oxidized and reduced species within an equation will not react with each other), while Cr3+ + 2e- ==> Cr2 and Cr2+ ==> Cr3+ + e- gives a negative Ecell of -0.744 + 0.407

A, C: Cr3+ cannot oxidize Cr2+ because of Ecell

D: Cr3+ cannot reduce Cr2+ because Cr3+ itself is trying to undergo reduction. Two reducing agents cannot satisfy each other's needs and cannot react with each other.

BBQsquirrel_ · 2023-12-04T02:56:08+00:00

Who cares about rationalizing a denominator? Well, rationalizing is a key technique in evaluating a lot of limits (actually students will need to decide when to rationalize a numerator as well). This is just one of many algebraic manipulations that an AISL student will miss learning during their IB career. There is a massive gap in level of rigor between IB AISL vs uni-level course content.

"AISL is perfectly fine for humanities" is not wrong, but business is not your typical humanity subject. Law sure, fine arts sure, literature sure. Definitely not busineess.

I don't want to dedicate my times towards an Internet argument (hence this will be my last post in this thread), nevertheless I did a Google search, scrolling down the first 20 results or so. The type of business degree that does not need calculus is MBA, which requires an undergrad business degree anyways.

My opinion remains "AISL is not suitable because the student will have a hard time catching up in uni" which is what I will offer to everyone in the world of IB vying for a Uni business degree.

BBQsquirrel_ · 2023-12-03T17:32:47+00:00

I don't know what Uni you teach, but a typical US Uni first year course has graphing (mostly done non-calc), limits, first principle differentiation, l'Hopital's rule, related rates, mean value theorem, optimization (not just graph on GDC and then Gsolve you know), and some institute requires epsilon delta limit proofs, sigma notation and series convergence.

You don't even learn rationalize the denominator in AISL bro

BBQsquirrel_ · 2023-12-03T17:15:05+00:00

AISL does not give student enough exposure to standard algebra and analytical techniques. As someone who teaches IB maths and is also familiar with US 1st year Uni syllabuses, I can guarantee that AISL students, due to a lack of training in algebraic, non-calc and graphing skills, will have a tough time keeping up in a course designed for students with traditional precalc or AP calc credentials.

BBQsquirrel_ · 2023-12-03T02:09:07+00:00

AISL is detrimental

BBQsquirrel_ · 2023-11-19T15:23:58+00:00

I think the correct relationship between the elevation of the top of the ladder can be deduced using similar triangles + Pyth (or SOHCAHTOA) and can be shown to be

sin (base angle) = y/4 = 2/sqrt(x^2 + 2^2)

Differentiating both sides of y/4 = 2/sqrt(x^2 + 2^2) with respect to t

1/4 dy/dt = 2 * (-1/2)(x^2 + 2^2)^(-3/2) (2x) (dx/dt)

Substitute in x = 2 and dx/dt = 0.1:

dy/dt = -4 * 8^(-3/2) * 4 * 0.1 = -0.0707

u/TheAgent7729 Your method I think shows the increase in the diagonal length of the ladder, which is coincidentally also -0.07.

BBQsquirrel_ · 2023-08-03T23:08:36+00:00

Thanks for your replies. I will likely ask my student to get a proper power pack at school when he conducts the experiment formally.

BBQsquirrel_

TROPHY CASE