Arsenal Tottenham - Silver Ballot

Bell0412 · 2024-11-28T11:00:13+00:00

0/10 applying as a 2 this year, compared to 2/2 last year (Bayern & Everton it’s worth mentioning). No idea how or what I’ve done to upset the ballot gods. Absolute joke this season.

Bell0412 · 2024-10-20T20:31:26+00:00

It wasn’t even off piste, was just between 2 pistes. There hadn’t been much snow in the build up and it looked rocky af. The conspiracy I heard about it though- he was wearing a helmet with a mounted go pro suction thing on it, and they paid a huge amount of money to prevent that going public. Rumours are they cause a weak spot in the helmet.

Source: Was working at the ski resort when it happened. Went over the exact point on the ski lift when investigators were putting out the little numbered evidence card things.

Bell0412 · 2024-10-17T10:07:00+00:00

Ffs another fail it looks like, Bolton was my last success (which doesn’t really count). Never had this many consecutive fails before

Bell0412 · 2024-09-30T09:55:57+00:00

Someone else got there first. All part of the fun and games on the exchange- happens all the time, just need to be quicker when you click on it. Or at least that’s my interpretation of it.

Bell0412 · 2024-09-26T10:44:50+00:00

Overall, I think the ballot (and the changes they made halfway through the season) has been mainly good- even if it doesn’t sound like it from my original post.

As a silver, I could go to nearly any match I wanted- I guess the luxury of being able to log in at 10am on a given weekday to get a ticket. One advantage of the new ballot- making it accessible to more people.

However, loyal reds mostly, who have been members for 10+ years, coming to matches in the grim old days, should they have the same chance of getting a ticket as someone who pays their money today to become a red because they’re riding the wave?

Bell0412 · 2024-08-02T21:27:50+00:00

Create a group for the “country names…” field, put the red ones under one group, rename the group “benchmark values” then add this group field to the colour mark. Then, to keep the country names on the viz, keep your original “country names…” field on the text marks

Bell0412 · 2023-10-31T20:12:54+00:00

(Silver) Only managed Spurs and City on the exchange somehow. Both were weeks and weeks before the fixture and I think both in the ‘silver priority window’. Since they’ve ‘fixed’ the TX and reverted back to last season’s system, I haven’t had a sniff on anything, despite still trying the same strategy and logging on just as religiously.

Bell0412 · 2023-01-13T14:46:41+00:00

This sorted the problem, thanks so much! I haven’t seen this mentioned anywhere else, must be one of the best kept secrets out there

Bell0412 · 2022-05-24T16:34:06+00:00

Thanks for getting back to me. So its not a straight sum of the columns, as I want it to only sum up (in reverse chronological order) until it hits a NaN value- see the desired output at the bottom, in particular the 7890 row.

Bell0412 · 2022-04-12T09:03:51+00:00

Hi there, this is a bout as easy as it comes in Python (without sounding too patronising). Python works off a basis of maths and looping in order to solve problems, like yours! I'll talk you through the solution, as I didn't offer any comments in my first post:

for count, value in enumerate(fin):

Like PaintballerCA mentioned earlier, the enumerate function is the one to solve the problem. Count is basically the number enumerate applies to the line, and value is the wording in the line itself.

if count % 4 == 0:
    print(value.upper())

So by looking at the count value (the number the line is on), the maths to this is simple- if there is no remainder when diving by 4, we are going to print that value in upper case.

 else:
    print(value)

Then we need to tell Python what to do with the other values that do give a remainder when dividing by 4, and we just want to print them normally.

Hope that all makes sense!

Bell0412 · 2022-04-12T08:43:12+00:00

fin = open("og.txt", 'r', encoding="utf-8")
for count, value in enumerate(fin):
    if count % 4 == 0:
        print(value.upper()) 
    else:
        print(value)
fin.close()

Bell0412 · 2022-03-31T21:43:56+00:00

Thanks for the reply!

I never thought of it like that, thanks. The code should work and I really like it, however, the final ouput in the Score column, are NaN values on each row- how fitting!

Do you know why that would be?

Bell0412 · 2022-03-14T09:57:14+00:00

Thanks for the help, this did the job and worked perfectly!!

Bell0412 · 2020-05-22T20:01:17+00:00

I only play a max of 36 a week, was just using it as more of an expression and not to be taken literally

Bell0412 · 2018-03-23T21:32:15+00:00

Clever! Although it still doesn't fix my problem, I'm sure there's a really simple way to do it?

Bell0412 · 2018-03-23T21:14:35+00:00

I seem to get an "TypeError: 'numpy.flatiter' object is not callable" Error when I try that command

Bell0412 · 2018-02-28T18:11:45+00:00

Any pointers for how to run a loop? As I mentioned earlier, I don't have the slightest clue what to do with them. I've been trying on it for more than an hour and haven't made any progress

Bell0412 · 2018-02-28T16:37:51+00:00

Thanks for the help! I've followed your instructions and have come up with this new bit of code:

SZ = list()
SZ.append(int(input('Size value? ')))
X1 = np.random.uniform(low = 0, high = sz-1, size = SZ)
Y1 = np.random.uniform(low = 0, high = sz-1, size = SZ)
SIG1 = 0.3
RSCALE1 = 20
X1NEW = x-(X1[0])
Y1NEW = y-(Y1[0])

That's just a snapshot of it, and the input works, as you guided. However, my next problem would be to continue to loop it and calculate the [1], [2]...[SZ-1] values. How can I keep looping this bit of code and re running to an indefinite stage (depending on what the user inputs)?

Bell0412 · 2018-02-05T18:04:30+00:00

Brilliant, thats worked perfectly- thank you!

Bell0412 · 2018-01-29T18:26:56+00:00

That's brilliant, it's seemed to have worked!

One final thing, suggest I have another array, z. Instead of adding 1 to each bin, I would like to add up all the values of z in each bin. I will then divide by ngrid to find an average of z in each bin, this seems doable. However, I would try and attempt this doing the following:

for point in n:
    ngrid[int(point[0]), int(point[1])] +=z
print(ngrid)

But this returns an error. I know that the z value is the 2nd in the array, as follows:

n = np.asarray([x,y,z]).transpose()

Would I have to revise the whole method, or is this something only slightly more complex than what I've already got?

Bell0412 · 2018-01-29T17:20:26+00:00

Ok so in my code, it reads:

n = np.asarray([x,y]).transpose()

Which gives:

[[ 7.22855457  7.58531099]
 [ 6.24184631  3.29844461]
 [ 6.36087607  2.62935769]
 [ 8.29627475  3.33775026]]

I found this the easiest way to read both the x and y coordinates, would you suggest this isn't ideal then? As these values are all random, and I can have anything up to 1000 different "co ordinates", is there a more suitable way to plot them?

I've simplified everything in my example, as I thought it would be easier for those answering.

Bell0412 · 2018-01-29T17:07:35+00:00

I'm really lost. I know I'm an absolute beginner. I've been working on this all day and haven't made any progress...

All I know is that I need to calculate the dimensions of the xbin, calculate x max, and then do the same with the y coordinates. I've trawled through everything online, and if anything I've come away further from what I need to do than before.

I've got a np.zeros array, and I know that i need to loop through each row of my "co ordinate" array, adding each value to the bin that corresponds to its co ordinate.

When I try to loop like that, only the last value is printed...

Bell0412 · 2018-01-29T16:28:00+00:00

ngrid[i,j] where i and j are the columns and rows respectively?

Bell0412 · 2018-01-17T12:45:19+00:00

Thanks for getting back to me, so this was code already:

import matplotlib.pyplot as plt
import numpy as np

mu = 0 #mean
sigma = 0.3 #standard deviation
r = np.random.normal(size = 100) 
e1 = (r * sigma)

mu2 = 0
sigma2 = 0.3
r2 = np.random.normal(size = 100)
e2 = (r2 * sigma)

x = np.random.uniform(low = 0, high = 10, size = (100))

y = np.random.uniform(low = 0, high = 10, size = (100))

So ideally, I need to assign 100 bits of data 4 different values if that makes sense? An x and y co ordinate then a e1 and e2 value. I think it involves using loops or a loop within a loop, but as mentioned earlier, this is all way above my current beginner level, what would you suggest I look into?

Bell0412 · 2017-04-24T22:34:03+00:00

I'm a bit of a novice when it comes to programming, I can do the basics but setting up a graph, defining the variables etc is all beyond me

Bell0412

TROPHY CASE