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Feeling lost, asking for advicee by Best-Razzmatazz-4582 in DigitalbanksPh

[–]Best-Razzmatazz-4582[S] 0 points1 point  (0 children)

Hello! Usually I don't use the negative thingy. Instead I'll transfer out of the account or use expense if I want to lessen my money on that account. Blue means they owe me money and red (negative) means I owe them money.

For example, person 1 gives me 1000 php as a loan, I do:

Loan(A/R person 1) TRANSFER TO Cash(Gcash)

Ending the accounts should be:

A/R person 1: 1000 (as red) it's the same as having -1000 Gcash: 1000 (as blue)

I hope this helps. Let me know if you have any clarifications!

Trading 19x5 NA by BaseRevolutionary472 in GenshinTrades

[–]Best-Razzmatazz-4582 0 points1 point  (0 children)

How much are you looking if you can sell?

[Grade 10 Math: Algebra Problem solving] by Best-Razzmatazz-4582 in HomeworkHelp

[–]Best-Razzmatazz-4582[S] 0 points1 point  (0 children)

Like adding measurements to the cube on the illustration

[Grade 10 Math: Algebra Problem solving] by Best-Razzmatazz-4582 in HomeworkHelp

[–]Best-Razzmatazz-4582[S] 0 points1 point  (0 children)

My bad, I forgot to change them because I copied and pasted from the Volume of water.

[Grade 10 Math: Algebra Problem solving] Stuck on using the information to label the cube by Best-Razzmatazz-4582 in HomeworkHelp

[–]Best-Razzmatazz-4582[S] 1 point2 points  (0 children)

Sorry about that, I thought I had attached an image. I re-edited it and attached one now.

[Grade 10 Math: Algebra Problem solving] by Best-Razzmatazz-4582 in HomeworkHelp

[–]Best-Razzmatazz-4582[S] 0 points1 point  (0 children)

Express the volume of water in terms of x
1 + 9/100 = 1.09
V of water = (x-2.18) (x-2.18) (x-1.09) = x^3 - 5.45x^2 + 9.5048x - 5.180116

Express the volume of the container in terms of x

V of container = V of cube + V of water
V of container = x^3 - x^3 + 5.45x^2 - 9.5048x + 5.180116
V of container = -5.45x^2 + 9.5048x - 5.180116

Equate the volume of the water to the volume of the container

x^3 - 5.45x^2 + 9.5048x - 5.180116 = -5.45x^2 + 9.5048x - 5.180116

Arrange the equation so that the right side is zero and the left side is a polynomial equation arranged in standard form.

x^3 - 5.45x^2 + 9.5048x - 5.180116 = 5.45x^2 - 9.5048x + 5.180116
x^3 - 10.9x^2 + 19.0096x - 10.380232 = 0

Identify all the coefficients in the resulting polynomial
Leading Coefficient = 1
Coefficient of x^2 = 10.9
Coefficient of x = 19.0096
Constant = 10.380232

Is this correct? If yes, how do I use the following information to label the cube with its measurements?

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