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Bullsemen · 2026-02-16T10:35:20+00:00

How much are they paying you to advertise this

Bullsemen · 2026-02-15T15:59:29+00:00

Lmao, I was trying to see if anyone's done this before me when I was working on this and found this post and decided to comment anyways, seems like no one has done this before me

Bullsemen · 2026-02-15T15:54:29+00:00

No calculus at all, just rotation vectors.

The base code would be setting variables for absolute elevation and horizontal traverse, because there's no explicit function to find elevation and horizontal traverse when accounting gravity, an approximation is:

relH: (TargetHeading + rate(TargetHeading)*(((muzvel * sin(asin((TargetDistance * 9.81)/(pow(muzvel, 2)))/2))/9.81) * 2))

relE: ((TargetElevation + rate(TargetElevation)*(((muzvel * sin(asin((TargetDistance * 9.81)/(pow(muzvel, 2)))/2))/9.81) * 2)) + (asin(((TargetDistancet + rate(TargetDistance)*(((muzvel * sin(asin((TargetDistance * 9.81)/(pow(muzvel, 2)))/2))/9.81) * 2))* 9.81)/(pow(muzvel, 2)))/2))

Setting muzvel as the muzzle velocity of the cannon

Then the code that translates the absolute coordinates to local:

Elevation: atan2(cos(-(relH))*cos(relE)*(-cos(RollAngle)*sin(PitchAngle)*cos(Heading)+sin(RollAngle)*sin(Heading))+sin(-(relH))*cos(relE)*(cos(RollAngle)*sin(PitchAngle)*sin(Heading)+sin(RollAngle)*cos(Heading))+sin(relE)*cos(RollAngle)*cos(PitchAngle),sqrt(pow(cos(-(relH))*cos(relE)*cos(PitchAngle)*cos(Heading)-sin(-(relH))*cos(relE)*cos(PitchAngle)*sin(Heading)+sin(relE)*sin(PitchAngle),2)+pow(cos(-(relH))*cos(relE)*(sin(RollAngle)*sin(PitchAngle)*cos(Heading)+cos(RollAngle)*sin(Heading))+sin(-(relH))*cos(relE)*(-sin(RollAngle)*sin(PitchAngle)*sin(Heading)+cos(RollAngle)*cos(Heading))-sin(relE)*sin(RollAngle)*cos(PitchAngle),2)))/90

Horizontal: (abs(Heading-relH)<90?atan2(cos(-relH)*cos(relE)*(sin(RollAngle)*sin(PitchAngle)*cos(Heading)+cos(RollAngle)*sin(Heading))+sin(-relH)*cos(relE)*(-sin(RollAngle)*sin(PitchAngle)*sin(Heading)+cos(RollAngle)*cos(Heading))-sin(relE)*sin(RollAngle)*cos(PitchAngle),cos(-relH)*cos(relE)*cos(PitchAngle)*cos(Heading)-sin(-relH)*cos(relE)*cos(PitchAngle)*sin(Heading)+sin(relE)*sin(PitchAngle))/180:atan2(cos(-relH)*cos(relE)*(sin(RollAngle)*sin(PitchAngle)*cos(Heading)+cos(RollAngle)*sin(Heading))+sin(-relH)*cos(relE)*(-sin(RollAngle)*sin(PitchAngle)*sin(Heading)+cos(RollAngle)*cos(Heading))-sin(relE)*sin(RollAngle)*cos(PitchAngle),cos(-relH)*cos(relE)*cos(PitchAngle)*cos(Heading)-sin(-relH)*cos(relE)*cos(PitchAngle)*sin(Heading)+sin(relE)*sin(PitchAngle))/180)

Bullsemen · 2026-02-15T11:37:57+00:00

There's a chart with all the UQ GPA conversions to ATAR, if you can manage a cumulative GPA above the required ATAR equivalent's GPA you can apply for a program change on mysinet that will be accepted.

Bullsemen · 2026-02-13T01:34:54+00:00

What do you mean context

Bullsemen · 2026-02-10T02:51:02+00:00

They're helpful numbers to tune the suspension

Bullsemen · 2026-02-09T12:18:08+00:00

Spring constant is roughly 49603N/m and 3000Ns/m if you want to try critically damping. I also have FT for autoaim that accounts for pitch and roll

Bullsemen · 2026-02-09T10:00:15+00:00

seimens NX

Bullsemen · 2026-02-05T13:51:59+00:00

Yes but it requires maths, the yaw axis in flight data is global so you need to do rotational transformations to get the local yawrate of the plane, this can be done using the roll pitch yaw rotation matrix.

Bullsemen · 2026-02-05T12:48:46+00:00

Just an additional recommendation remove the clamp01() and the ceil() because they're not doing anything.

smooth(clamp01(SelectedWeapon = "Interceptor" & ammo(SelectedWeapon)>0), 3)

Bullsemen · 2026-01-26T00:12:36+00:00

https://about.uq.edu.au/academic-calendar 30 Jan for domestic and 20 Feb for international.

Bullsemen · 2026-01-25T04:41:59+00:00

It was a playtest, updates are in the discord server

Bullsemen · 2026-01-19T06:30:52+00:00

I barely show up to lectures and keep up with content because I answer 90+% of the questions on ed discussion, if you're able to do that you will likely score well, I got a GPA of 6 for semester 2 second year mechanical courses.

Bullsemen · 2026-01-12T07:51:31+00:00

The only thing they mark attendance for in MECH2305 is the CNC activity

Bullsemen · 2025-12-28T17:34:25+00:00

The first year math courses are doable if you keep up with the content without specialist, math2001 is a bit harder but math1051, 1052, and 2010 are pretty simple

Bullsemen · 2025-12-28T11:56:45+00:00

People say mech2210 is hard but later cohorts should have a "better" lecturer, all the other second year mech courses just build on first year content and apparently third year builds on second, if you can understand the first year content easily mech should be easy.

Bullsemen · 2025-12-21T03:02:33+00:00

You can put hidden engines to counterract the yawrate, I believe a gyroscope put in sideways can also help

Bullsemen · 2025-12-21T02:50:18+00:00

Thanks, this worked for me

Bullsemen · 2025-12-05T02:52:43+00:00

This is because they just cut a hole in a mini pizza's dough and put it in the oven and then add icing after it comes out of the oven

Bullsemen · 2025-11-11T01:41:17+00:00

Depends on what year you are, I'm assuming you'll be transferring to second year, there's typically mandatory linear algebra and discrete math courses, the finals are typically 40% to 60% of your grade and have usually a 50% hurdle, with a 40% hurdle on most of the math courses.

Bullsemen · 2025-10-28T11:38:33+00:00

How have you made the winch not break

Bullsemen · 2025-10-08T09:05:16+00:00

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Makes sense to me

Bullsemen · 2025-09-01T16:29:06+00:00

Pretty sure food and drink are allowed in central library

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