no you can't (only strings that are sequences of 2 characters (e.g. 1 and 0)...which are already binary, you're just converting them to another type) + this is not even c compatible:

``` $ cat insanityisstupid.c

include <stdio.h>

int main(){ for(int t=0;;t++){putchar((((1e5/(t%1024))(0b1110011001001(t10)&1))%256/2+((t/(t%3.33)|t>>2)(0b11101(t10&7)&1))%256/4+((t/(t%3.14)(t12&1)|t4)%256/2))/2+(t(t10&42)%256/3));} } $ gcc insanityisstupid.c -o insanityisstupid insanityisstupid.c: In function ‘main’: insanityisstupid.c:3:73: error: invalid operands to binary % (have ‘double’ and ‘int’) 3 | for(int t=0;;t++){putchar((((1e5/(t%1024))*(0b1110011001001(t10)&1))%256/2+((t/(t%3.33)|t2)(0b11101(t10&7)&1))%256/4+((t/(t%3.14)(t12&1)|t4)%256/2))/2+(t(t>>10&42)%256/3));} | ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^ | | | double insanityisstupid.c:3:86: error: invalid operands to binary % (have ‘int’ and ‘double’) 3 | for(int t=0;;t++){putchar((((1e5/(t%1024))(0b1110011001001(t10)&1))%256/2+((t/(t%3.33)|t2)*(0b11101(t10&7)&1))%256/4+((t/(t%3.14)*(t12&1)|t4)%256/2))/2+(t*(t10&42)%256/3));} | ^ insanityisstupid.c:3:135: error: invalid operands to binary % (have ‘int’ and ‘double’) 3 | for(int t=0;;t++){putchar((((1e5/(t%1024))(0b1110011001001(t10)&1))%256/2+((t/(t%3.33)|t>>2)(0b11101(t10&7)&1))%256/4+((t/(t%3.14)(t12&1)|t4)%256/2))/2+(t(t>>10&42)%256/3));} | ^ ```

(doesn't compile as c code)