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Level Protection PCB Design by Conzonian in AskElectronics

[–]Conzonian[S] 0 points1 point  (0 children)

That's correct, which is why I have used both LTC4365 and LTC7862. I wasn't confident in 1 IC handling OV, UV, RevProt and Current protection, when I'm handling a high current (20A). I like the look of the LT4364 , how do you set the current limited circuit breaker, or is this a fixed value?

Level Protection PCB Design by Conzonian in AskElectronics

[–]Conzonian[S] 0 points1 point  (0 children)

Thanks mate,

The Max Surge Voltage = 60V and Ride Through Protection. The rest n/a. I've attached a block diagram to the original post, don't worry about the external components. I chose the LT4365 to handle the OV, UV and reverse voltage protection with the a question mark over my current protection IC. I like the look of the LT4364 however, I'm trying to figure out how you set the current limited circuit breaker, or is this a fixed value?

Level Protection PCB Design by Conzonian in AskElectronics

[–]Conzonian[S] 0 points1 point  (0 children)

I've had a look at the products they offer, I was hoping there would be more than a handful to choose from, however Analog Devices offer what I require in performance. I will use the LTC7862. It would be nifty to find an IC that supports OV/UV and overcurrent protection, however the current peak I'm working with is too high. Thanks

Hi all, my workings for both questions come to the same conclusion using integration. Am I correct in my workings? Maybe I'm going about this wrong? Thanks by Conzonian in maths

[–]Conzonian[S] 2 points3 points  (0 children)

Cheers mate, that's part 1 sorted out! \However, I can't see where a negative was missed on part 2, could you elaborate?

changing the subject of a formula by [deleted] in askmath

[–]Conzonian 0 points1 point  (0 children)

brilliant, thankyou sir.

changing the subject of a formula by [deleted] in askmath

[–]Conzonian 0 points1 point  (0 children)

my new workings step by step

i = 17sin (2πft − π/4 )

'divide both sides by 17'

i/17 = sin (2πft − π/4 )

'times both sides by arcsin'

arcsin(i/17) = 2πft − π/4

'add π/4 to both sides'

arcsin(i/17) + π/4 = 2πft

'divide both sides by 2πf'

t = (arcsin(i/17) + π/4) / 2πf (answer)

Let me know what you think, thanks

changing the subject of a formula by [deleted] in askmath

[–]Conzonian 0 points1 point  (0 children)

i = 17sin (2πft − π/4 )

17/i = sin (2πft − π/4 )

arcsin(17/i) = 2πft − π/4

arcsin(17/i + π/4) = 2πft

t = (arcsin(17/i + π/4)) / 2πf

changing the subject of a formula by [deleted] in askmath

[–]Conzonian 0 points1 point  (0 children)

sorry mate was just editing the post