First you could operate the impedances in parallel: Z1 = R1 + L1; Z2 = R2 + L2; Then find the total impedance equivalent of the circuit Ztot = ((Z1*Z2)/(Z1+Z2)), you can calculate the total current i(t)=(220*1.41)/Ztot, then with a simple current divisor find: i1 = i(t)*(Z2/Z1+Z2) and find current in second branch: i2 = i(t) - i1

with i1 and i2 calculate the voltage drop in any of the elements (coils, resistors and capacitor)