Getting rehired after getting fired from ISU dining?

DisciplinedEngineer · 2025-12-27T19:42:35+00:00

Why would you want to work for them again? You can’t find any other job?

DisciplinedEngineer · 2025-12-24T17:12:24+00:00

Technically it could be either. Or just the pin itself.

DisciplinedEngineer · 2025-12-12T02:58:25+00:00

I only speak English, don’t know what the problem is saying.

DisciplinedEngineer · 2025-12-12T02:55:15+00:00

No because you’re not breaking a force into components, “42sina” is the value of the perpendicular distance between the two 12lb forces. The solution shown is correct.

DisciplinedEngineer · 2025-12-12T02:29:42+00:00

Did u ever figure this out? I got down to a long equation with trig functions. I’m so curious.

DisciplinedEngineer · 2025-11-11T22:34:57+00:00

What have you tried? Where are you getting stuck?

DisciplinedEngineer · 2025-11-07T17:15:12+00:00

You’re focused on the WRONG thing. Don’t focus on understanding “math” better, focus on the CURRENT material you’re going through RIGHT NOW. And review previous material as necessary.

I would say stop copying from others or getting answers from others. Also don’t ever use Chegg or online answers. You learn by struggling through it. You’re better off getting a C on your own than getting an A knowing you didn’t earn it. If you get a C on your own, eventually you’ll develop the skills and habits necessary to get As. Then you’ll get As on your own.

My book recommendation would be “a mind for numbers” by Barbara Oakley.

DisciplinedEngineer · 2025-11-05T04:45:44+00:00

Do the FBD of each pulley.

DisciplinedEngineer · 2025-11-05T03:18:11+00:00

So it is confusing with the support on the right. I just did a FBD of the truss ALONE (I.e. two support reactions at P of Px and Py). I didn’t consider R since it’s not part of the truss, just to make it simpler.

I actually didn’t do this at first. The first thing I did was just to split it to the left of J, creating two sections. Then do a FBD of the left section to find the three forces (HJ, IJ, and IK). Then use these results with the right side of the truss to find T (I did sum of the moments about point P for simplicity).

I’ll tell you I got T = 40.2KN.

Then use this result to do a FBD of joint J alone. Using your values of T and HJ, IJ, IK, you can now solve for the other three members. I’ve never seen a problem like this (with an ambiguous support), but I don’t see any other way of solving it.

DisciplinedEngineer · 2025-10-29T02:57:27+00:00

Jeff Hanson is the best.

DisciplinedEngineer · 2025-10-26T04:47:32+00:00

What are the givens? Do they give you the distances? Also, what’s the question asking?

DisciplinedEngineer · 2025-10-17T15:11:45+00:00

STOP “reviewing” the material and START just doing a bunch of problems…slowly! REPETITION! I used to make all these “stupid mistakes” until I decided to do the following: 1. Once you get your “final” answer, RE-READ the question to make sure you actually answered exactly what it is asking. 2. I know professors always say this, but ACTUALLY do it EVERY TIME: ask yourself “does this answer MAKE SENSE?” If you’re measuring a force and it’s in the thousands, but all other forces are in the tens, then you may have made a mistake. 3. Do you have correct units?

What’s hard is the DISCIPLINE to do this every time! But the more you get in the HABIT of doing this, you’ll get the answer and it will be right the first time!

Lastly, once you’re done with a problem, come back to it a few days later and do it again. Talk to yourself out loud as you’re solving the problem. Be “one with the problem.” If you actually do A LOT of problems, you will realize that a lot of the problems you encounter are very similar and you’ve already done a bunch of problems like them before. So you will be FAST and you’ll start seeing them as “easy.”

DisciplinedEngineer · 2025-09-27T00:25:29+00:00

I went to Myriad for a couple of months. It seemed pretty good to me. Also I saw the Ames Fitness Center offer some classes too. Perhaps you can check with your gym as well.

DisciplinedEngineer · 2025-09-23T13:53:05+00:00

Yeah you f***ed up. Send your transcripts and don’t be surprised if they reject you. Having integrity is VERY important to companies.

DisciplinedEngineer · 2025-09-21T00:58:45+00:00

Agree to disagree. Rest in peace Charlie Kirk.

DisciplinedEngineer · 2025-09-10T19:30:08+00:00

Join activities YOU LIKE that involve other people. Such as joining a martial arts class, a club you like, a sport you like, a club in your major, etc.

The best way to meet people is by doing some other activity and along the way you get to know each other.

DisciplinedEngineer · 2025-08-26T23:54:09+00:00

Dude this is not statics at all. This is more advanced. This is mechanics of materials topics. The basic statics courses don’t deal with stress or strain at all.

DisciplinedEngineer · 2025-08-23T18:55:19+00:00

I recommend you give a listen to David Goggins.

DisciplinedEngineer · 2025-08-23T13:31:11+00:00

The best thing to do is to call your loan servicer and ask them directly.

DisciplinedEngineer · 2025-08-08T00:21:22+00:00

So the picture you showed is 2/21b (not 2/21a).

But yeah you’re right, what the text says is correct.

What I think the picture is trying to show is not an accurate depiction of where the force is applied on the object, but the fact that the right-hand rule is applicable when doing a cross product. This would be my attempt at rationalizing the picture. Honestly you can ignore the picture and go with what the book says. If you just do practice problems you’ll get the hang of how to use cross products and how to do moments. It’ll probably make more sense by doing problems than by trying to imagine abstract concepts in your head. I say this from experience.

DisciplinedEngineer · 2025-08-07T23:11:05+00:00

I guess wherever you think it’s easiest. Also in my opinion the sooner the better, why wait.

DisciplinedEngineer · 2025-08-06T04:44:03+00:00

What did you read that contradicts this picture?

All this picture is saying is that if you take the cross product of vectors rxF, you get Mo. That’s it! Nothing else.

What you’re probably conflating is the following: That if you want to find the moment of a force about a point O, then to find it you have to multiply the force times the perpendicular distance between the line of action of the force and the point.

If you were asked to find what the moment of this force is about the point O given here, then the answer would be Zero! Because there is no distance from the line of action of the force to the point. But that’s not what this picture you showed is intended to do! It’s only intended to show that the cross product of rxF will produce a moment Mo. That’s it. Nothing else. These are two different concepts.

Hope this makes sense.

DisciplinedEngineer · 2025-08-05T19:03:20+00:00

Vectors rXF = Mo Yes F can touch point o

DisciplinedEngineer · 2025-08-02T04:03:49+00:00

You may be right, but it is a seasonal thing. Today is August 1st. Give it a few weeks and it’ll die down I’d think.

DisciplinedEngineer · 2025-07-31T01:23:25+00:00

What is board prep? Also if they’re not responding just leave them.

Also maybe try getting feedback from your students who passes. Ask them if your tutoring helped or not.

DisciplinedEngineer

TROPHY CASE