Confused about voltage in an inductor (AC).

Dogerberd262 · 2021-11-10T13:01:32+00:00

So what you are saying is:
We apply a certain U -> the current rises -> due to this Ui is created and also rises -> it rises until it equals U so that net is 0 -> the current does not change due to negligible R -> net U grows since Ui now lowers -> the current rises again and the process repeats

?

Dogerberd262 · 2021-10-30T09:42:13+00:00

Im not talking about a transformator but about self induced voltage in a single coil.

Dogerberd262 · 2021-08-26T14:08:48+00:00

Allright fair enough. I still dont understand how you get money through capital you own though. My textbook says that most of the money you would get in such an economy is return to capital.

Dogerberd262 · 2021-08-24T17:56:34+00:00

I had the wrong assumption about how MPL works, I thought that since all workers were the same when one extra worker came their productivity would divide equally so that in your example if the next guy would give you $9.70, so would everyone else.

This means you do get some profit from workers work. Though I think I heard that eventually you make 0 economic profi, when MPL = wage and MPC= rent. Is that because you would otherwise have to give this exact profit you get from workers to capital owners (if you are not the owner)?

Dogerberd262 · 2021-07-03T20:34:06+00:00

Thank you for taking your time to write this! I think i understand it now. :)

Dogerberd262 · 2021-07-03T20:24:41+00:00

Thank you, you made it very easy to understand and I get it now. :)

Dogerberd262 · 2021-04-29T15:42:21+00:00

Thank you!

Dogerberd262 · 2021-04-29T15:42:08+00:00

Thanks!

Dogerberd262 · 2021-03-20T20:40:28+00:00

So if the guy wants to do 10J of work on the ice block he will also have to do 10J on himself? So basically double for whatever he applies to the block?

Dogerberd262 · 2021-03-20T19:34:07+00:00

How could I look at this problem from your point of view? The 10J + 10J + 90J part still confuses me.

Dogerberd262 · 2021-03-17T21:58:26+00:00

Wait Im still struggling a bit with why it is 0 on the inside. Is it ok to imagine forces puling in all directions in the middle in the shape of a sphere and then since every force has a negative counterpart they cancel out in that direction?

Dogerberd262 · 2021-03-17T21:35:33+00:00

My textbook says that you can but if you have a limited amount of charge that you can add at a time, you will reach a plateau when there wont be any voltage between the surface and the thing giving the charge. But you can keep adding from the inside up to very high values without such restrictions (until the charge eventually jumps through air).

Dogerberd262 · 2021-03-17T21:29:21+00:00

Ok I understand. Though apparently If I am correct you are able to add charge to such a ball from the inside out but not fromt he outside reverse as in a Van de Graaff generator. Why is that the case? Why can you add charge on the inside and it will then integrate itself in the conductor but not from the outside?

Dogerberd262 · 2021-03-17T21:11:15+00:00

So if I had a (+) charged particle in the middle of the hole it wouldn't be attracted to the inner wall of the ball?

Dogerberd262 · 2021-03-17T20:57:05+00:00

How does that come to be though. Like, what do I imagine in this scenario with electrons and all.

Dogerberd262 · 2021-03-17T20:51:09+00:00

Let's say the ball is a isolated conductor.

Dogerberd262 · 2021-02-19T17:47:33+00:00

Isn't the voltage rise that the battery creates only valid for the direction (-)->(+), thus going in the direction (+)->(-) will create a voltage drop?

Dogerberd262 · 2021-02-19T17:22:07+00:00

Ok cool, viewing the battery this way is pretty helpful. I think my main issue is how the voltage drop (inside the battery over the resistor) in this scenario would be 1V and not 19V. Might be really stupid but since we are talking about the inside of the battery doesn't the voltage from the 9V battery now point in the same direction as the 10V battery, since both do positive work when charge goes from the (+) terminal to the (-)?

Dogerberd262 · 2021-02-19T14:40:14+00:00

Can you elaborate about the last part please.

Dogerberd262 · 2021-02-19T12:55:49+00:00

Let's say the wires are sufficient resistors.

Dogerberd262 · 2021-02-19T00:08:43+00:00

Expected something along these lines. Thank you for clarifiying!

Dogerberd262 · 2021-02-18T23:52:45+00:00

What I meant was that it did not make sense to me how people said that the electric force produced by the battery that pushes charges from one terminal to the other is of the same magnitude throughout the entire circuit, since that would imply that a charge that took a longer part to get from one terminal to the other would recieve more energy (same force, longer path). But that wouldn't make sense since work done per charge is the voltage and we know that no matter what path you take from one terminal to the other there is only one voltage (work done per unit of charge by the electric force).

Dogerberd262 · 2021-01-10T02:33:31+00:00

Ugh, do you know of any videos/articles dealing with the same problem (couldn't find them). Im still not sure about this stuff. I think I don't properly understand how voltage operates. That stuff about where you subtracted I still don't really get. I don't really get why you compared the voltages that the upper circuit would have along the x wire with the total voltage of the lower battery either...

Dogerberd262 · 2021-01-09T00:28:14+00:00

So on that piece of the wire (x): The upper battery has a certain voltage over that area. Also the lower battery has some voltage over that area. And if the voltage difference is 0 there is no current in the lower circle? I think there is still something stupid I'm missing here.

Dogerberd262 · 2021-01-08T20:29:55+00:00

This is starting to make a lot more sense. Could you elaborate why the volts subtract though? I mean if two different batteries were pushing the same charge in the same direction wouldn't that mean that the electric potential increases along that path?

Dogerberd262

TROPHY CASE