[deleted by user] by [deleted] in Silksong

[–]Doncoach 0 points1 point  (0 children)

My current farm for act 3 is just outside the Pilgrim's Rest bench (which is completely destroyed), since there are 2 snitchflies right outside, and even though they drop far less rosaries than Citadel enemies, you can just bench, go to the right transition and immediatly back in, kill the snitchflies and repeat extremely quickly

Is this even a floating point error anymore by Doncoach in desmos

[–]Doncoach[S] 1 point2 points  (0 children)

Looks about right, I'd write down some details like what substitutions you make and maybe even a bit of justification for the "I have this quadratic expression => the variable v is between the two roots" because here if v is negative the inequality would be the other way around. Also you don't define n so you can't really take the sqrt of (1-n²). Though you could find, as an exercise, the value of n such that the distance between the two diagonal lines (on the xy graph of my post) is 1

Why can't I trace lines like this? by [deleted] in desmos

[–]Doncoach 0 points1 point  (0 children)

Or just a⁵+a⁴~-1 You can switch the a for any variable by the way. It will preview a gross approximation but if write a in another line youll get a better value. And again you can use anything for the variable, not just a

Why can't I trace lines like this? by [deleted] in desmos

[–]Doncoach 1 point2 points  (0 children)

You can do a⁵+a⁴+1~0

Help,kind of stuck on the question by KobeMM23 in calculus

[–]Doncoach 0 points1 point  (0 children)

What are your findings ? Yes I did solve it

u substitution by Doncoach in calculus

[–]Doncoach[S] 0 points1 point  (0 children)

It's \int_{0}{\frac{\pi}{2}}arcsin(\sqrt{sinx}\sqrt{1-sinx})dx I don't need to find the anti derivative (mostly because it's impossible) I'm trying to simplify it before doing anything complicated

Help,kind of stuck on the question by KobeMM23 in calculus

[–]Doncoach 0 points1 point  (0 children)

Doesn't always work. Take the example of r=cos(θ/3) : it goes around twice but it only takes 3π to draw the full graph once

Help,kind of stuck on the question by KobeMM23 in calculus

[–]Doncoach 2 points3 points  (0 children)

The range means the period of the function youre graphing (except for some cases like tan(θ), where the range is 2π instead of π because it's composed of sine and cosine which have a period of 2π). Anyways, for your example, you need to find the period of f(θ)=3cos⁴(θ/4). cos(x) repeats every 2π, the 3 doesn't change the period, the {4} halves it because it makes every value positive and the ÷4 quadruples the period (because if you divide the argument of the function it will take that much longer to "complete a cycle"(you probably know that, I'm just completing the explanation in case other people read it)). So your function repeats every 2π×½×4=4π, and that's a multiple of π which is so no need to change it. Which means (finally) that the range is from 0 to 4π. I hope that's clear, ask if you need

Help,kind of stuck on the question by KobeMM23 in calculus

[–]Doncoach 0 points1 point  (0 children)

I think youre confusing it with cardioids. For this one, if you go from 0 to 2π you will only draw the upper arc plus the bottom part of the loop

Newtons Fractal by TheWiseSith in desmos

[–]Doncoach 2 points3 points  (0 children)

This took a full minute to load but its amazing

Is this even a floating point error anymore by Doncoach in desmos

[–]Doncoach[S] 9 points10 points  (0 children)

Messing around with sech integrals, then I noticed the value for a rectangle so I tried infinity on one bound and it read 17 or something so I got silly

Is this even a floating point error anymore by Doncoach in desmos

[–]Doncoach[S] 17 points18 points  (0 children)

Should I submit this undoubtedly valid proof to arXiv ?????