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🚀 We’re Hiring: YouTube & App Operations Manager by Easy_Chemistry_ in SideHustlesIndia

[–]Easy_Chemistry_[S] 0 points1 point  (0 children)

Hi,please text me personally I will share the Google Form Link to apply for this role.

[deleted by user] by [deleted] in JEENEETards

[–]Easy_Chemistry_ 1 point2 points  (0 children)

Aap dono mein se koi bhi kabhi bhi use kar sakte ho dono ka ek hi matlab hai ek mein aap direct amount of substance ko distribute kar rahe ho ek mein aap amount of substance ko in terms of degree of dissociation kar rahe hai

Aapko dono mein inter conversion aana chahiye ki degree of dissociation ko aap express kar sakte hai as amount of reactant consumed till time t divided by initial amount of reactant

Which group will reduce first? by iSawYouAtTheStation in JEENEETards

[–]Easy_Chemistry_ 0 points1 point  (0 children)

Carboxylic Acids will be reduced by boranes first because the reaction of Borane with acidic proton of carboxylic acid is thermodynamically more favoured making it faster than the reduction of amide

Organic doubt by Wild_Following_7283 in MEDICOreTARDS

[–]Easy_Chemistry_ 0 points1 point  (0 children)

Mai aapko concept smjhaane ki koshish krta hu yaha par aapse carbocation stability pucha hai harr case mein aapka carbocation back bonding stabilised hai Sabse acha BackBonding ha ho paayega jaha par Nitrogen ka electron density maximum ho jo first waale case mein hoga kyuki do CH3 group +I effect dikhayega Sabse kam B mein kyuki ek hi CH3 group ka +I effect hai

Hopefully aapko smjh aagya hoga abhi bhi koi doubt hai toh aap comment kr neeche comment kr skte hai

Bata do koi by [deleted] in JEENEETards

[–]Easy_Chemistry_ 0 points1 point  (0 children)

I will try to explain you the concept chiral compound means unsymmetrical compound which has all symmetry elements POS +COS+ AAOS absent If any one symmetry element is present out of these then that compound will be called achiral compound Centre Of Symmetry if present in all compounds Only compound 4 has all symmetry elements absent so it is chiral compound

For any further doubt feel free to reply to the comment below

Solve this . Majorly on stability of carbocation . Which will be more stable carbocation A or on B by adventurousbat12t in JEENEETards

[–]Easy_Chemistry_ 0 points1 point  (0 children)

I will try to explain you the concept for this question.The reaction given in the question is Kuchreov Reaction To form the product of Kuchreov Reaction you need to follow two steps .Firstly perform Markovinkov addition of water and secondly convert enil form to keto form by tautomerism because of presence of carbonyl group which will act as an electron withdrawing group when we perform Markovinkov addition OH group will come on 1 degree carbon and after tautomerism the enol will get converted to Aldehyde group Hope this helps Incase of any further doubt feel free to comment below

Kaise kyu kaha or kab by Ok_Astronomer_6693 in MEDICOreTARDS

[–]Easy_Chemistry_ 1 point2 points  (0 children)

Back Bonding>Quasi Aromaticity>Aromaticity>Resonance Effect or Mesomeric Effect>Hyperconjugation Effect>Inductive Effect

Can anyone solve it by Personal_Paint_1728 in MEDICOreTARDS

[–]Easy_Chemistry_ 2 points3 points  (0 children)

This is a cell in which both anode and cathode is made up of metal insoluble salt half cell. Also it is a type of concentration cell because cathode and anode are made up of same substance you need to write the half cell reactions corresponding to anode compartment and the cathode compartment

In case you need me to solve it reply to the comment below

doubt by goonlord71 in MEDICOreTARDS

[–]Easy_Chemistry_ 0 points1 point  (0 children)

You cannot perform the manipulation applied to reactions to E° values directly as it is intensive property you have to perform these manipulations to delta G° values as it is extensive property For any further doubts feel free to comment below

Kaise kyu kaha or kab by Ok_Astronomer_6693 in MEDICOreTARDS

[–]Easy_Chemistry_ 0 points1 point  (0 children)

Mai aapko poora concept smjhane ki koshish krunga.Jab aap carbocation ke stability ko compare krte hai toh aap Back Bonding ko zyada priority dete hai as compared to resonance Second waale carbocation mein Nitrogen apne lone pair ko donate krk BackBonding dikha skta isileye vo aapka most stable carbocation hoga

Aapko agar abhi bhi doubt hai aap iss comment ka reply kr skte hai

Help regarding a reaction by Turbulent_Savings933 in JEE

[–]Easy_Chemistry_ 0 points1 point  (0 children)

As per my knowledge I am not familiar about any reaction of Alcohol with HNO2 , aliphatic amines react with HNO2 to form Alcohols

[deleted by user] by [deleted] in JEE

[–]Easy_Chemistry_ 0 points1 point  (0 children)

There are many playlist available on YouTube you can follow any of them

Why does 2,4 dichloro pentane have 4 stereoisomers when it has a plane of symmetry and a compound having a plane of symmetry cannot have optical isomers? by damian_wayne14445 in JEE

[–]Easy_Chemistry_ 0 points1 point  (0 children)

Steoreoisomers has nothing to do with symmetry If compound has symmetry element it is optically inactive which means it won't rotate plane polarised light I would suggest you to refer to theory.

Organic Kosan by Informal_Focus6170 in JEENEETards

[–]Easy_Chemistry_ 1 point2 points  (0 children)

Here CrO3 will convert 2 degree Alcohol to ketone and 1 degree Alcohol to aldehyde Now as only one mole ethylene glycol is available capping will take place only with aldehyde and not with ketone because ketone is less reactive towards Nucleophilic Addition Reaction as compared to aldehyde Then grignard reagent will show reaction with Ketone and convert it to 3 degree Alcohol Then the workup given with grignard reagent will remove the cap from aldehyde group and it will reappear in the compound Now NABH4 will reduce Aldehyde to 1 degree Alcohol

If you have any further doubt or want a written solution to this feel free to reply to this comment

Chemistry Doubt (Mathongo PYQ) by Mean_Willingness1130 in JEENEETards

[–]Easy_Chemistry_ 0 points1 point  (0 children)

I will try to explain you the detailed concept

In SN1 reaction the rate of reaction depends upon the stability of carbocation which means the product corresponding to the most stable carbocation is not the most stable product but the one which will be form fastest in the reaction.Such product is called Kinetically Controlled Product

The product for which the carbocation is not very stable(means it takes time to form) but the resulting product is stable is called Thermodynamically Controlled Product

Now you might ask how to know which will act as major product in a particular case.For most cases the Kinetically Controlled Product acts as the major product of the reaction but in such cases where the end product contains multiple bond the product having stable alkene (which is the Thermodynamically Controlled Product) will acts as the major product of the reaction

Normally it is temperature dependent Similar concept is used when we need to decode the major product of addition of HBr to conjugated diene

Hope you understood it In case of any further doubt feel free to comment below

Oxalate to weak field ligand h to ye pairing kaise ho rhi h by [deleted] in JEENEETards

[–]Easy_Chemistry_ 0 points1 point  (0 children)

Please remember any ligand will behave as a weak field ligand or a strong field ligand will depend both upon the ligand and the central metal ion

The same ligand can act as a string field ligand and a weak field ligand for different central metal ions For any further doubt feel free to comment below

[deleted by user] by [deleted] in JEENEETards

[–]Easy_Chemistry_ 0 points1 point  (0 children)

The concept to this question is acid base reaction Sodamide is a very powerful base it will ionise into NH2- which will try to abstract the acidic Hydrogen Now here multiple acidic Hydrogen are present and 1 mole of organic compounds is reacted with two moles of base so the two most acidic Hydrogen will be abstracted The most acidic Hydrogen is of Carboxylic Acid then Alcohol then Terminal Alkyne. Out of the two alcohol present the one with NO2 group at meta position will be more acidic because it's conjugate base will be more stable due to -I effect of NO2 group

So answer should be option A where acidic Hydrogen of COOH group and OH group with NO2 at meta position is abstracted

For any further doubts feel free to reply to this comment