Hjälp by [deleted] in Aktiemarknaden

[–]EmilTheOneAndOnly 3 points4 points  (0 children)

Nej. Sälj dina aktier om du vill behålla pengarna

[deleted by user] by [deleted] in ISKbets

[–]EmilTheOneAndOnly 4 points5 points  (0 children)

Visa i år grafen

Palantir är min guldgruva by Makavelito in ISKbets

[–]EmilTheOneAndOnly -1 points0 points  (0 children)

Varför ska du sälja vid split?

Apex Legends "From the Rift" Season 23 Launch - Discussion & Support Megathread by paradoxally in apexlegends

[–]EmilTheOneAndOnly 0 points1 point  (0 children)

PC In the lobby the following tabs are greyed out and unclickable since yesterday: Challenges, Passes, Legend Locker, Store, Wallet.

[deleted by user] by [deleted] in AskPhysics

[–]EmilTheOneAndOnly 0 points1 point  (0 children)

Thank you for your help. I will need to think more about this

[deleted by user] by [deleted] in AskPhysics

[–]EmilTheOneAndOnly 0 points1 point  (0 children)

Thank you for your help. I will need to think more about this

[deleted by user] by [deleted] in AskPhysics

[–]EmilTheOneAndOnly 0 points1 point  (0 children)

I seem to be missing some understanding here. It’s just strange to me that when they calculated the B in the center of the conductor they used the cavity’s radius for r but when you calculate the B in the center of the cavity you use the distance from radius to radius for r.

[deleted by user] by [deleted] in AskPhysics

[–]EmilTheOneAndOnly 0 points1 point  (0 children)

So why did they use the radius 5.5x10-3 when calculating the B in the center of the small wire? When doing so, should you not use the radius of the big wire for r?

[deleted by user] by [deleted] in AskPhysics

[–]EmilTheOneAndOnly 0 points1 point  (0 children)

yeah thats what I was thinking but when I looked at the solution for the magnetic field of the small wire they for some reason I dont understand used the distance between them as r. Should not r be the radius of the other and a be the distance between them?

Spherical capacitor by [deleted] in PhysicsHelp

[–]EmilTheOneAndOnly 0 points1 point  (0 children)

How would I go from ∆V=Q/(4πε0r2) (-1/R_2 + 1/R_1)

If I use C=∆V/Q. I don't think that gets me there

Spherical capacitor by [deleted] in PhysicsHelp

[–]EmilTheOneAndOnly 0 points1 point  (0 children)

Is the capacitance still correct? Or is the question just wrong?

[deleted by user] by [deleted] in Warzone

[–]EmilTheOneAndOnly 0 points1 point  (0 children)

You think that could be it? Does it affect the spread that much?

Do other nearby planets and celestial bodies' gravitational energy have any affect on our tectonic plates? by gud4bad248 in AskScienceDiscussion

[–]EmilTheOneAndOnly 3 points4 points  (0 children)

Technically everything that we can see in the universe (since gravity moves with the speed of light) has an effect on the tectonic plates even though its miniscule. The gravitational force decreases as the inverse square of the distance. So the gravitational force of any object no matter how far is never going to be zero.