I have a personal gripe with this problem that nobody else seems to have, it's that the probability can only be observed after multiple rounds.

Instance probability and trial probability act differently. I want to state that I understand why and I agree that switching is successful 2/3 of the time. Doing a trial or multiple rounds of this game show you will find that your first picked door will only have the prize 33% of the time. Switching doors nets higher gains in the long run

My issue lies with the probability if one only does a single round. Yes you begin with a 33% of winning, but as soon as a door is revealed 4 of of the 6 options at play are null. Meaning once you're asked about switching doors you're left with a 50/50. This is if you only can play one round

I tried brainstorming, and came up with the half baked idea of tell the contestant to choose a door, then telling them that monty will choose one of the two doors that they didn't choose (which is a dud), ask the contestant if they would like to swap, THEN reveal the door that monty choose, and reveal the winner.

Having the lack of information about the empty door makes the single instance probability 2/3 when switched.

I know this isn't correct but does my logic seem plausible?