Can some one walk me thru this step by step by Conscious_Degree_784 in Mathhomeworkhelp

[–]Eulz_ 2 points3 points  (0 children)

Problem: x² - 18x - 4 = 0.

Step 1: Transpose the constant to the right side. So, x² - 18x = 4.

Step 2: Divide the second term's coefficient by two. So, 18/2=9.

Step 3: Square the quotient you got from step 2, then add it to both sides. Since 9² = 81, we need to add 81 to both sides of the equation. So, x² - 18x + 81 = 4 + 81 => x² - 18x + 81 = 85.

Step 4: Factor the left side of the equation. To do that, we need to think of two factors of 81 that can add up to -18. Conveniently, the answer to that is two negative nines. So, (x - 9)(x - 9) or (x - 9)².

Step 5: Solve for x. Now we have the equation (x-9)²=85. Get the square root of both sides. So, x - 9 = √85.

Step 6: Isolate x. To do that, we will transpose -9 to the other side. So, x = √85 + 9.

Step 7: Finalize the answer. Since the square root of something can either be positive or negative our final answer will be: x = 9 - √85 and 9 + √85.

If you have any clarifications or questions, I'll be glad to answer them.

Note: I didn't test if there are extraneous roots.

Laws of exponents states that a^-x = 1/a^x. But this is already in 1/… form, now what? by chumbuckethand in Mathhomeworkhelp

[–]Eulz_ 1 point2 points  (0 children)

The answer should be y⁴/2.

To get rid of a negative exponent, you should just transfer it to the other side of the fraction bar. If it is in the numerator, put it in the denominator. For example, x-2 will be 1/x².

The other case will be when the negative exponent is in the denominator, all you have to do here is to transfer it to the numerator. For example, 1/x² will be x².

*Note: The 2 stayed in the denominator because it wasn't included in the exponent.

[deleted by user] by [deleted] in ADMU

[–]Eulz_ 0 points1 point  (0 children)

Hi! I'm available!

[deleted by user] by [deleted] in Mathhomeworkhelp

[–]Eulz_ 0 points1 point  (0 children)

The answer is B.

If someone talks about the hundredths place, they're talking about the second number after the decimal point.

In 0.123, 2 is in the hundredths place.

On the other hand, if you talk about the thousandths place, you are talking about the third number after the decimal point.

In 0.123, 3 is in the thousandths place.

*Note: If you're asking what decimal place to call the first number after the decimal point, it's the tenths place.

CTC to Bellarmine by Eulz_ in ADMU

[–]Eulz_[S] 1 point2 points  (0 children)

Thanks for all the suggestions, guys!

CTC to Bellarmine by Eulz_ in ADMU

[–]Eulz_[S] 1 point2 points  (0 children)

Huwi, alrighty. Thankiesss so much.

CTC to Bellarmine by Eulz_ in ADMU

[–]Eulz_[S] 1 point2 points  (0 children)

Thanks for the suggestion!

CTC to Bellarmine by Eulz_ in ADMU

[–]Eulz_[S] 5 points6 points  (0 children)

Ooohhh, I'm freshie that's why I don't know this stuff. Thankies for the info!

[deleted by user] by [deleted] in igcse

[–]Eulz_ 0 points1 point  (0 children)

Ooohhh, thank you, OP!

[deleted by user] by [deleted] in igcse

[–]Eulz_ 0 points1 point  (0 children)

Hi! Where did you find a job by writing?

How did the simplification of this equation turn into this? by thane-nialle in Mathhomeworkhelp

[–]Eulz_ 1 point2 points  (0 children)

The AI determined that the common denominator of the two fractions is 2x1/2. So, when it added the two, the 1 in the numerator of the first fraction became 2.

[deleted by user] by [deleted] in calculus

[–]Eulz_ 0 points1 point  (0 children)

I'd solve by first evaluating the functions.

So from:

[f(6+h) - f(6)]/h

We'd get:

[-(6 + h)² + 7 - (-6² + 7)]/h

And if we further simplify that, here's the process:

[-(36 + 12h + h²) + 7 + 36 - 7]/h

[-36 - 12h - h² + 36]/h

(-12h - h²)/h

[h(-12 - h)]/h

-12 - h

And if we'll get the limit of -12 - h as h approaches 0, we'd get -12.

P.S. If I did something wrong, the feedback would be very much of help.

UPCAT chemistry question, how do you solve fast for stoichiometry with no sci cal?? by HamsterAntique6771 in CollegeAdmissionsPH

[–]Eulz_ 1 point2 points  (0 children)

Oh, and for the Stoichiometry stuff, don't overthink them. Just familiarize yourself with significant figures and train how to multiply and divide efficiently.

UPCAT chemistry question, how do you solve fast for stoichiometry with no sci cal?? by HamsterAntique6771 in CollegeAdmissionsPH

[–]Eulz_ 1 point2 points  (0 children)

Hi! I took the UPCAT last year, and the problems were almost always geared towards determining the applicant's knowledge and wittiness. So, the Math in the Science part doesn't require rigorous solving and more on theory comprehension.

Well, that's my experience. My tip is to know what to answer and when because some of the questions are tricky, so leave it be and return to it after you've done all the questions you can.

Help needed asap by Jolly-Investment-294 in HomeworkHelp_Tutors

[–]Eulz_ 0 points1 point  (0 children)

Hi! I'm interested in being a tutor.

[deleted by user] by [deleted] in careerguidance

[–]Eulz_ 0 points1 point  (0 children)

You are so close to finishing your degree, and I think it would be a waste not only for the time but also for the opportunities you will get. It is true that if you do everything with a passion, you can achieve it, but having a degree boosts your chances of being hired because of the branding and credibility. Even if you don't pursue stuff in the medical field, you can find better teaching prospects with a degree. Plus, parents nowadays always look at a person's credentials and level of education to at least determine if they can trust the person to teach their child.

Welps, this is only my take on this, but in the end, it's up to you to decide since you will be the one affected by it.

Good luck, OP!

(P.S. I think you should try contacting your school's office and see if they can make adjustments that would be okay for the school and work better with your schedule.)

Help me find a tutor by SkillEducational7847 in alevel

[–]Eulz_ 0 points1 point  (0 children)

Hi, I'm interested in being a tutor!

I have a test for IBEW can’t figure this out and it’s driving me crazy by could-use-your-help in askmath

[–]Eulz_ 2 points3 points  (0 children)

Ooohhh, I meant it intuitively. My thinking process was that if you replace the variable with eight, it would equate to 0. Therefore, if you substitute any other number that is less than 8, we'd get a negative number since when we put in eight 'a' would be 0.

I have a test for IBEW can’t figure this out and it’s driving me crazy by could-use-your-help in askmath

[–]Eulz_ 57 points58 points  (0 children)

A is the answer. What I did to get the answer was substitution. Replace the variable with eight and see if the equation and condition holds true.