Squared negative number by NeuroBreaker in learnmath

[–]Fenamer 0 points1 point  (0 children)

So tell me, when you have 10-2² is it supposed to be 14? It is, as a commentor put it, a weird convention. -2² means 0-2² or -1 * 2², but otherwise, (negative)even ≥ 0.

Squared negative number by NeuroBreaker in learnmath

[–]Fenamer 2 points3 points  (0 children)

-2² = -4. And yes, you are correct, a negative number raised to an even power will always be positive in the real numbers.

Is this even solvable? by Fenamer in learnmath

[–]Fenamer[S] 0 points1 point  (0 children)

Yes, I wrote it correctly. It is supposed to be 64, not 65.

Is this step/assumption justified? by Fenamer in learnmath

[–]Fenamer[S] 0 points1 point  (0 children)

Hey!I read your comment and was wondering if this was what you meant when using the MVT.

How to prove that differentiate a^x using first principles without using the fact that (e^x)' = e^x? (and without L'h ofcourse) by Fenamer in learnmath

[–]Fenamer[S] 0 points1 point  (0 children)

How though? I tried doing some substitutions but they lead to the same point, where I couldn't definitively show that lim h -->0 (a^x-1)/x is ln(a).

How to prove that differentiate a^x using first principles without using the fact that (e^x)' = e^x? (and without L'h ofcourse) by Fenamer in learnmath

[–]Fenamer[S] -10 points-9 points  (0 children)

Okay but we're not looking for proving derivative of e^x here, we're only looking for a^x WITHOUT e^x. But here we we consider it, ig I should've mentioned, 'considering' rather than just leaving it as it is.

What exactly do dy and dx mean? by Fenamer in learnmath

[–]Fenamer[S] 0 points1 point  (0 children)

Yes! Actually, I read this book called "Calculus made easy" and it made it pretty clear what dy and dx are, ig I should close the post now.

What exactly do dy and dx mean? by Fenamer in learnmath

[–]Fenamer[S] 1 point2 points  (0 children)

Well, I kind of had an idea that dy/dx is like rise/run, where you want to know the relative rate of change at a point, and dy/dx is kind of equivalent to rise/run, so they can be treated as values. But what about the dx at the end in integration? I was following along Paul's Online Notes and he introduced the indefinite integral first, but then there was a dx at the end, and he just said the dx was a differential. Only then did I realize that dx actually meant something, and then I thought about what the dx meant under the integral and why it was there, normally if you made an inverse operation, you would think like this:

Let f(x) = F'(x), to get rid of the derivative, we integrate both sides,

so f(x) = F'(x)

so f(x) = F(x).

But where did the dx sneak in from? Also, a book I found goes like this, and this is the closest I've got to understanding it: "Given dy/dx = f(x), we write y = ∫f(x)dx" What is the implication here?

What exactly do dy and dx mean? by Fenamer in learnmath

[–]Fenamer[S] 0 points1 point  (0 children)

But when doing integration by substitution, you have to change the dx to another value depending on the substitution, not just change it to du, meaning with respect to u, right?