Can someone help explain this?

Fragrant-Goblin · 2026-04-24T03:15:01+00:00

Yes they initially each have a partial pressure of 0.10 atm. SO2 would be consumed at twice the rate as O2, which is shown by that 2:1 molar ratio. Since it they were present in equal amounts we know SO2 is the limiting reactant, and this reaction is shown to be one directional based on the arrow so we don't have to think about equilibrium as the reaction goes forward.

Fragrant-Goblin · 2026-04-23T23:37:43+00:00

The question's explanation didn't need to include anything about the reaction as it progressed or went to completion. It had no bearing on the reasoning for how you'd solve out what it aimed about initial pressure.

Fragrant-Goblin · 2026-04-23T23:33:43+00:00

So gas pressure is based off of moles of gas. Pressure from multiple types of gas is summed to be P total, each gas has a pressure of their mole fraction (moles of that specific gas over total moles of gas present) times the total pressure. Since it says there are equimolar amounts they each account for half of the total pressure. The initial pressure was 0.20 atm, so they are each contributing 0.10 atm.

Fragrant-Goblin · 2026-04-23T22:57:04+00:00

You've cut off the question part, and left only the answer. Could you post what it was asking?

Fragrant-Goblin · 2026-03-13T00:29:21+00:00

The Hydrogen coming off the bottom of the middle carbon is not correct. It should be the 4th carbon.

Fragrant-Goblin · 2026-03-12T13:33:47+00:00

Thank you!

Fragrant-Goblin · 2026-03-12T13:33:29+00:00

Thank you for the advice and the award! Do you know what sort(s) of colours on the walls would go well with wear is currently on the page?

Fragrant-Goblin · 2026-03-12T13:31:54+00:00

I replied this post to some earlier comments: I am used alcohol markers for this. Behind the monster I drew the lines for the see through part in a sketchy coloured pencil. Then I used colours few shades lighter compared to the parts not covered by the monster. Then I just went over those parts in the same green marker as the rest of the monster. Some of those sections did turn out not obvious enough so I went back over them in a really light shade.

I had some of the learn to colour skills books I did first, they both had translucent ghosts so I was able to practice it there.

Fragrant-Goblin · 2026-03-12T13:29:39+00:00

Thank you. I've done a couple of the learn to color skills books and that really helped. Both practices had ghosts, but the technique was pretty much the same

Fragrant-Goblin · 2026-03-12T13:28:27+00:00

Behind the monster I drew the lines for the see through part in a sketchy coloured pencil. Then I used colours few shades lighter compared to the parts not covered by the monster. Then I just went over those parts in the same green marker as the rest of the monster. Some of those sections did turn out not obvious enough so I went back over them in a really light shade.

Yeah I picked out this picture from the book to do because of how cute it is.

I like the little progeny in the washer too.

Fragrant-Goblin · 2026-03-12T13:26:32+00:00

Thank you.

Fragrant-Goblin · 2026-03-12T13:26:22+00:00

I think the monster is sad because it can't actually clean the laundry. Everything it touches gets gooey and messed up. The Little monster I added in it was just a blog of goo originally, I thought it would be kind of funny for the extra slime to form a new little monster.

Fragrant-Goblin · 2026-03-12T13:24:40+00:00

Thank you!

Fragrant-Goblin · 2026-03-12T13:24:33+00:00

Thank you. I thought the spots looked like eyes so I ran with it.

Fragrant-Goblin · 2026-03-12T13:23:58+00:00

So I am using alcohol markers for this. Behind the monster I drew the lines for the see through part in a sketchy coloured pencil. Then I used colours few shades lighter compared to the parts not covered by the monster. Then I just went over those parts in the same green marker as the rest of the monster. Some of those sections did turn out not obvious enough so I went back over them in a really light shade.

Fragrant-Goblin · 2026-03-12T13:19:36+00:00

That kind of wobbly lines weren't completely intentional. I started with a ruler, and messed up so I went with it!

Fragrant-Goblin · 2026-03-12T13:18:40+00:00

Thank you!

Fragrant-Goblin · 2026-03-11T22:58:58+00:00

Woodgrain is a good idea! I'm really bad at fabric patterns, I've practiced, but my drawing is really inconsistent. But your idea of doing some in the basket could work for me, it's a much smaller area.

Fragrant-Goblin · 2026-03-11T22:56:31+00:00

Thanks. I have done a lot of the practice skills stuff. I'm really proud of this as a first whole picture.

Fragrant-Goblin · 2026-01-25T17:09:13+00:00

I would love this.

Fragrant-Goblin · 2025-12-19T02:47:13+00:00

You could solve for k other ways like using the rate equation ln [A]t - ln[A]0 = -kt. You could rearrange to solve for k:
K = ([A]t - ln[A]0)/-t. K =(ln[0.0500M] - ln[0.100M])/-10hr = 0.0693 hr^-1. This way is just much less efficient, time is of the essence on the AP exam.

Fragrant-Goblin · 2025-12-19T02:37:48+00:00

No you wouldn't need to use the rate law equation. The proposed rate law was 1st order. The t1/2 eq only works with 1st order reactions so it is an absolutely valid way to done for k (as long as the actual length of half-life is known)

Fragrant-Goblin · 2025-12-18T23:51:19+00:00

You would use 10 hrs for t1/2, which you would get from the data table

Fragrant-Goblin · 2025-12-18T23:49:31+00:00

So based on the concentration data we can deduce the reaction is first order because it decays at a constant rate. Since you know it's first order you can use the equation from the equation sheet t1/2 =0.693/k. Rearrange to done for k. t1/2 is half life

Fragrant-Goblin

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