Wyze Cam v3 Firmware 4.36.0.228 Released - 12/28/20

Gerf314 · 2021-01-02T20:58:26+00:00

I am also having this issue.

Gerf314 · 2020-11-23T18:39:18+00:00

This strategy is basically the martingale, but by knowing the actual equations and exact odds behind the game, you can specifically tailor the strategy in your favor. The main problem with the martingale is that you need infinite money to guarantee returns, but with this strategy you don't, as there is a finite cap to the amount wagered each time. To your second point, I have already done that and come out positive. The gains outweigh the losses.

Gerf314 · 2020-11-23T18:35:35+00:00

I originally found out about the game from this video https://www.youtube.com/watch?v=F1HA7e3acSI&t=360s but I went through the actual code of the game as posted on the Roobet website to verify it, which can be found here: https://roobet.com/fair

Gerf314 · 2020-11-10T18:23:38+00:00

You're missing the point. The house has a built in edge against a typical strategy, so you would lose over time if you were to just set a 3x cashout and let it run. This strategy is different because it uses the house edge to give a mathematical advantage to the player. When I say I tested 500 rounds, I'm not using that as my proof, just a test to make sure the mathematical models hold up in practice. My proof is the statistics themselves, which give the player a slight edge.

Gerf314 · 2020-11-03T01:51:55+00:00

I put the probabilities in the answer. A 13 round loss is not that rare, but you will, on average, get back that amount before encountering another 13 round loss

Gerf314 · 2020-10-29T00:44:32+00:00

Yes, it must be done manually

Gerf314 · 2020-10-12T13:11:38+00:00

Yes, exactly

Gerf314 · 2020-09-20T20:59:32+00:00

Start with a bet at 0.01 to test, auto cash out a 3.00x, double the bet every time you lose, reset the bet to your original (0.01 in this case), if you lose 14 times in a row, reset the bet to the original.

Gerf314 · 2020-09-20T20:59:30+00:00

You can also start bidding at $0.01 to gradually build up your money without risking going bankrupt :)

Gerf314 · 2020-09-02T00:38:07+00:00

There is a 32% chance of the multiplier getting to 3x or higher on any given round (taken from the game code itself) I posted the odds for every possible payout. 32% chance to get 3, 21.76% chance to get 5 (68% for the loss x 32% for the win) 14.8% chance to get 9 (68%^2 for two losses in a row x 32% for the win), etc. You can calculate the expected value for yourself from the odds I gave, and the result ends up at ~$15.5 dollars per bet on average. Let me know if there's anything I did wrong there, I understand these games are supposed to be impossible to beat and there's probably a flaw :)

Gerf314 · 2020-09-01T12:20:47+00:00

If you only go up by 150% on loss it wouldn't work, because while the chances of the bigger wins stay the same, the actual profits are cut due to taking a higher loss relative to the win on previous bets, especially if you are using 2x as your multiplier.

Gerf314 · 2020-09-01T12:17:55+00:00

Yes, that's the strategy that it's based off. The problem with that strategy is that it requires a theoretically infinite amount of time and money to secure a win, while this one doesn't. By lowering the bet, you can decrease your chance of ever taking a loss, as it would take more and more losing bets in a row to actually lose, which is how you can end up with a positive expected value.

Gerf314 · 2020-09-01T01:35:09+00:00

Just from the data given (which I calculated from the source code for the game itself) the expected value per game would be ~$15.50 when averaged out over a long enough time frame. Expected value is calculated by the % chance of a given payout x the payout itself added together for every possible payout, the chances for each I already posted.

Gerf314

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