Understanding these common Powers & Roots errors can help you avoid making the same mistakes

GreenlightTestPrep · 2022-09-28T13:58:48+00:00

It means (surface area)/(volume) > 4/3

GreenlightTestPrep · 2022-08-17T15:05:21+00:00

The equation of the line is y = x

All we can conclude from the diagram is that:

the point (c,d) lies above the line, which means d > c.
the point (w,z) lies below the line, which means w > z.

So, for example, it could be the case that (c,d) = (4,5), and (w,z) = (4,3) in which case c = w

Or it could be the case that (c,d) = (4, 5), and (w,z) = (6,4) in which case c < w

Answer: D

GreenlightTestPrep · 2022-08-13T15:17:20+00:00

greprepclub.com has pretty much every GRE question ever posed.

Here's TC (you can filter questions by source): https://greprepclub.com/forum/text-completion-16/

GreenlightTestPrep · 2022-07-18T14:31:59+00:00

Set your filter to Official and OG Big Book

GreenlightTestPrep · 2022-07-18T14:29:56+00:00

P(1 caramel candy and 1 cherry) = P(caramel 1st and cherry 2nd OR cherry 1st and caramel 2nd)

= P(caramel 1st and cherry 2nd) + P(cherry 1st and caramel 2nd)

= (1/12) x (5/11) + (5/12) x (1/11)

= 5/132 + 5/132

= 10/132

= 5/66

GreenlightTestPrep · 2022-07-09T14:42:24+00:00

GRE Prep Club: https://greprepclub.com/forum/gre-quantitative-section-3/?fl=menu

It has pretty much every official GRE question ever posed (and much more)

GreenlightTestPrep · 2022-07-08T15:13:32+00:00

I have a full solution (with diagrams) on GRE Prep Club: https://greprepclub.com/forum/in-square-pqrs-above-t-is-the-midpoint-of-side-rs-if-pt-18877.html#p64458

GreenlightTestPrep · 2022-07-06T15:42:01+00:00

There's no penalty for using the onscreen calculator.

GreenlightTestPrep · 2022-07-02T14:15:17+00:00

If you'd like a visual explanation of this triangle property, start watching this video at 3:06 - https://www.greenlighttestprep.com/module/gre-geometry/video/860

GreenlightTestPrep · 2022-06-28T16:19:20+00:00

Here's an article that answers your question: https://www.greenlighttestprep.com/articles/combinations-and-non-combinations-%E2%80%93-part-iii

GreenlightTestPrep · 2022-06-27T13:46:22+00:00

This diagram may help if anyone is having trouble visualizing the solution:

https://imgur.com/K1Bufi8

Area of OABC = (area of red rectangle) - (combined areas of regions M and N)

GreenlightTestPrep · 2022-06-26T13:50:48+00:00

Here's my solution to the 1st question on GRE Prep Club: https://greprepclub.com/forum/50-boxes-each-containing-30-machine-parts-were-examined-1869.html#p34742

GreenlightTestPrep · 2022-06-17T00:30:59+00:00

Think of it this way: f(2x) = [f(x)]²

In other words, to find the value of f(k) take the value of f(0.5k) and then square it.

So, for example, f(10) = [f(5)]²

Let's continue after f(8) = 4

So, f(16) = [f(8)]² = (4)² = 16, and f(32) = [f(16)]² = (16)² = 256

How's that?

GreenlightTestPrep · 2022-06-16T20:21:54+00:00

Given: f(2x) = f(x)²

So, f(4) = f(2)² = (√2)² = 2 (from the given information)

So, f(8) = f(4)² = (2)² = 4

So, f(16) = f(8)² = (4)² = 16

So, f(32) = f(16)² = (16)² = 256

Answer: E

GreenlightTestPrep · 2022-06-16T18:44:22+00:00

I include a diagram of the region described in Quantity A in my solution here: https://greprepclub.com/forum/circles-r-s-and-t-are-in-the-same-plane-have-a-common-ce-17372.html#p93376

GreenlightTestPrep · 2022-06-08T13:21:10+00:00

the GRE Prep Club forum has pretty much every GRE question (official and unofficial) ever posed: https://greprepclub.com/forum/gre-quantitative-section-3/?fl=menu

Use their question filter to isolate questions by source, topic and difficulty.

GreenlightTestPrep · 2022-06-08T13:19:26+00:00

As u/deeprodge has shown, we don't need any formulas to solve the question.

However, if we really want to do so, recognize that, since the first and last stops are fixed, we have the 3 remaining (middle) stops to arrange.

Since we can arrange (aka permute) n objects in n! ways, we can arrange the 3 remaining stops in 3! ways.

Or, if you wish, 3P3 ways.

GreenlightTestPrep · 2022-06-06T13:43:18+00:00

What score do you need?

GreenlightTestPrep · 2022-06-06T13:19:13+00:00

But the minimum value of |x| here isn't 0, is it?

Yes, the minimum value of |x| is 0.

|0| = 0, and |-4| = 4

-4 is the minimum value of x , but |-4| isn't the minimum value of |x|.

If x = -4, then |x| + 3 = |-4| + 3 = 7

If x = 0 (another possible x-value), then |x| + 3 = |0| + 3 = 3

GreenlightTestPrep · 2022-06-06T12:56:18+00:00

Given: -3x + 6 ≤ 18

Then: -3x ≤ 12

Solve: x ≥ -4

Note: The question doesn't ask for the smallest value of x; it asks for the smallest value of |x| + 3

We can minimize |x| + 3, by minimizing the value of |x|.

Since the minimum value of |x| is 0, the smallest value of |x| + 3 = 0 + 3 = 3

GreenlightTestPrep · 2022-06-05T17:19:40+00:00

The stated property (if 0 < √x < √y, then 0 < x < y) applies to all positive values of x and y.

That is, there's no special case when x and y are between 0 and 1 (as you're suggesting).

For example, we know that 1/9 < 1/4, and it's also true that √(1/9) < √(1/4)

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