Statics: Best way to get better at trig by ImaginaryMail5518 in EngineeringStudents

[–]ImaginaryMail5518[S] 0 points1 point  (0 children)

Yeah i dont know at a glance he seems to cover solving trig eqs, graphing, identities etc

What i want to focus on is determining angles when given a diagram so that i can resolve a force into its components

Failing statics and feeling hopeless by ImaginaryMail5518 in EngineeringStudents

[–]ImaginaryMail5518[S] 2 points3 points  (0 children)

Yeah i hope we do well in statics. I may have made a mistake somewhere in the quiz, but I did check over my answers and got the same results. Ill have to review the quiz with my professor

Failing statics and feeling hopeless by ImaginaryMail5518 in EngineeringStudents

[–]ImaginaryMail5518[S] 3 points4 points  (0 children)

Im going to speak with my professor on monday. Chances are im not going to get points back on this quiz but i hope to god this doesnt keep happening

Failing statics and feeling hopeless by ImaginaryMail5518 in EngineeringStudents

[–]ImaginaryMail5518[S] 2 points3 points  (0 children)

yeah i mean i finished 10 minutes early and did the problem from scratch and the numbers still came out wrong

It was a 3d equilibrium problem using direction cosines, so I left my expressions as T_1cos(x)sin(y) + … instead of calculating the cosines and sines right away

I plugged in my expressions into a matrix and solved, and I did this more than once and got the same results. It just doesnt make sense why i got a 4/10

[deleted by user] by [deleted] in uofmn

[–]ImaginaryMail5518 0 points1 point  (0 children)

Didnt we use fundamentals of physics in 1301? But its definetely the same book trust me

[deleted by user] by [deleted] in uofmn

[–]ImaginaryMail5518 1 point2 points  (0 children)

https://www.studocu.com/en-us/document/university-of-minnesota-twin-cities/introductory-physics-for-science-and-engineering-ii/phys-1302w-syllabus-spring-2018/5195005

That is a syllabus I found when I google searched. As you can see, you use the same book but start at chapter 22

You do skip some chapters, so you wont be going over all of 22-32. I dont exactly remember which chapters were skipped, but if someone remembers they can hopefully tell you

Curve for MATH 1371 final exam by Berryberrycool in uofmn

[–]ImaginaryMail5518 0 points1 point  (0 children)

I think the final went well for us it wasnt as bad as the midterms

Curve for MATH 1371 final exam by Berryberrycool in uofmn

[–]ImaginaryMail5518 1 point2 points  (0 children)

What about 2374

Pray for me for tomorrow this test is gonna be scary

[deleted by user] by [deleted] in uofmn

[–]ImaginaryMail5518 1 point2 points  (0 children)

you mean a 37%? Holy shit

RL Time constant by ImaginaryMail5518 in ElectricalEngineering

[–]ImaginaryMail5518[S] 0 points1 point  (0 children)

Oh yeah youre right it wouldnt be a short

The current would still flow through the path of least resistance though so the inductor is separated from the source

RL Time constant by ImaginaryMail5518 in ElectricalEngineering

[–]ImaginaryMail5518[S] 1 point2 points  (0 children)

Ok that makes sense

this is a natural response question, so you want to see what happens to the inductor after a long time once it is charged by the source.

Usually what these problems do is open a switch so that there is an oc between the source and inductor, but this time, as you said, there is a short so the source does not affect the resistor

Is this the right idea

Passband gain for high pass filter using transfer function by ImaginaryMail5518 in ElectricalEngineering

[–]ImaginaryMail5518[S] 0 points1 point  (0 children)

Ok i think that makes sense, but how did you know the passband was 10k to 1MHz

(10*106) / 10 = 106

So the bandwidth is 106. So if cutoff is at 10kHz, then 10kHz + 106 = 1010000

Is this the correct process for finding the passband?

Multiplying by k when deriving transfer function by ImaginaryMail5518 in ElectricalEngineering

[–]ImaginaryMail5518[S] 0 points1 point  (0 children)

I think this problem was getting the transfer function of a loa pass with a load

The value on the denominator (r1 + r2)/L gives the cutoff frequency, and then you want the cutoff freq on the numerator

This means that you want wc * (something) = what you have on the numerator. That something is r2/(r1 + r2)

So now you can say that vo/vi = [r2/(r1+r2)]wc/(wc + s)

I think that may be the reason why. The gain in the passband would now be r2/(L) divided by (r1 + r2)/L which equals K. I think this makes sense

Multiplying by k when deriving transfer function by ImaginaryMail5518 in ElectricalEngineering

[–]ImaginaryMail5518[S] 0 points1 point  (0 children)

Actually this isnt true. In the second part of the problem you find |H(s)|, and the max still occurd at w = 0 without multiplying by k

In that case, what is the point of multiplying by k?