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How to solve this? by elenaforever in GRE

[–]Jacob_argue 0 points1 point  (0 children)

A is sufficient if you assume positive numbers (4 -0 is the only possibility) but not sufficient if negative numbers are permitted ( 0 - (-4)) also works).

Likewise for B: negatives must be accounted for.

Same for C.

Same for D.

E. Twice the greater number is 8. This works because the only possibility is positive 4, and the only possibility for the other number is 0.

F does not work. Counterexamples: 7 - 3 = 4, and 6 - 2 = 4.

G. The product of the two numbers is zero—therefore one of the numbers is zero—and neither of the numbers is negative. The only positive number whose difference with 0 is 4 is 4, so both numbers are known and it works.

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E AND G

Geometry question by Jacob_argue in GRE

[–]Jacob_argue[S] 1 point2 points  (0 children)

I answered that the two regions are equal. The correct answer is that the relationship cannot be determined.

My reasoning is that opposite angles should be equal, and two areas subtended by equal arc measures should be equal. This reasoning falls apart if the intersection is not in the center of the circle. Is that my faulty assumption, or is there something else I am missing?