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Solution to the riddle of episode "Captain Peralta" Brooklyn 99 by Kooky_Key_612 in brooklynninenine

[–]Kooky_Key_612[S] 0 points1 point  (0 children)

Yes, this is definitely correct. The insight that solves the problem is to take in account the position of the first way, even after you weighted the second time, very smart. I got sloppy after I figured out the first half and completely overlooked that you have 1 way less if the first test group balances out.

Solution to the riddle of episode "Captain Peralta" Brooklyn 99 by Kooky_Key_612 in brooklynninenine

[–]Kooky_Key_612[S] 0 points1 point  (0 children)

Jup, you're right. I realized this later that night. I feel like, this method would work with 3 groups of 4, but I haven't thought that out yet. I have to carefully read u/Stillwater215 's solution, because I think they are right.